arduino语法代码错误



我现在遇到的问题是arduino uno编程软件要求我在void之前加一个逗号或分号(sketch_apr04b:16:错误:应在'void'之前加','或';'),我不知道为什么,当我这样做时,告诉我同样的答案。

这是我的代码

#include <Servo.h>;  
Servo servo;
void setup () {
  servo.attach(9);
  servo.write(0);
  Serial.begin(9600);
}
  int seconds = millis()/1000;
  int degs = 0;
  int time = 0;
  int runs = 0
void loop() {
  // put your main code here, to run repeatedly:
  seconds = millis();
  while(time <= 28) {
  Serial.write(seconds);
  degs = map(time, 0, 29, 0, 179);
  servo.write(degs);
  delay(1000);
  }
  runs = runs + 1;
  time = seconds * (runs*29)
  servo.write(0);
  time = 0;
}

您的代码有三个语法错误:

错误1:

所有分号都用于标记语句的结束#include不是语句,因此不应包含分号。

错误2和3:

和以前一样,分号用于语句的分隔符。然后你应该把它包括在两行中。

#include <Servo.h>;  <----------------------- ERROR 1
Servo servo;
void setup () {
  servo.attach(9);
  servo.write(0);
  Serial.begin(9600);
}
  int seconds = millis()/1000;
  int degs = 0;
  int time = 0;
  int runs = 0 <----------------------------- ERROR 2
void loop() {
  // put your main code here, to run repeatedly:
  seconds = millis();
  while(time <= 28) {
  Serial.write(seconds);
  degs = map(time, 0, 29, 0, 179);
  servo.write(degs);
  delay(1000);
  }
  runs = runs + 1;
  time = seconds * (runs*29) <--------------- ERROR 3
  servo.write(0);
  time = 0;
}

您忘记了两个';'在'int runs=0'和之后

'时间=秒*(运行*29)'。

在arduino C中,每一行都必须以结束

您忘记了后面的分号";"

time = seconds * (runs*29)

int runs = 0

当您声明"runs"变量时,缺少两个";",而在"time=seconds*(runs*29)"上

    #include <Servo.h>;  
    Servo servo;
    void setup () {
      servo.attach(9);
      servo.write(0);
      Serial.begin(9600);
    }
      int seconds = millis()/1000;
      int degs = 0;
      int time = 0;
      int runs = 0 <---- HERE
void loop() {
  // put your main code here, to run repeatedly:
  seconds = millis();
  while(time <= 28) {
  Serial.write(seconds);
  degs = map(time, 0, 29, 0, 179);
  servo.write(degs);
  delay(1000);
  }
  runs = runs + 1;
  time = seconds * (runs*29)<----- HERE
  servo.write(0);
  time = 0;
}

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