爪哇游戏.需要在不使用中断语句或 system.exit 的情况下停止代码

Question

对于以下代码，我需要通过键入单词"quit"来停止代码，但不要使用"break"或"system.exit"语句。 有人可以帮助我吗？我认为布尔值可以解决这个问题，但我不知道如何使用它。我将 quit 语句放在循环的前两行，但我不确定它是否属于那里。我正处于学习阶段，所以不要太严格:)）

import java.util.*;
public class Game {

public static void main (String[]args){
    Game guessing = new Game();
    guessing.start();
}
public void start() {
    System.out.println("Welcome to guessing game!"); 
    System.out.println("Please enter the number between 1 and 1000");
    Scanner input = new Scanner(System.in);
    String playerName;
    String currentGuess;
    String quit = "quit";
boolean playGame = true;
int tries = 0;  //number of times player guessed
int guess = 0;  //number that player inputs
long startTime = System.currentTimeMillis();  //start timer after first guess
int randomNumber = (int) (Math.random() * 999 + 1); // generating random number
System.out.println(randomNumber);     // to be deleted after game is finished
currentGuess = input.nextLine();

do{
if (currentGuess.equalsIgnoreCase(quit)) {
        System.out.println("Thanx for playing");}

    if (currentGuess.matches("[0-9]+")) {
        int PlayerGuessInt = Integer.parseInt(currentGuess);
    }
    else {
    System.out.println("You have netered non-numeric value,please try again");
    currentGuess = input.nextLine();
    continue;
    }
    guess = Integer.parseInt(currentGuess);

    if(guess<1 || guess>1000 ){
        System.out.println("The number is out of range! Please try again");
        currentGuess = input.nextLine();
        continue;
    }
    if (guess>randomNumber){
        System.out.println("Oops,too high!");
        currentGuess = input.nextLine();
        tries++;
    }
    else if (guess<randomNumber){
        System.out.println("Sorry, to low!");
        currentGuess = input.nextLine();
        tries++;
    }

}
while (guess!=randomNumber);

    if (guess==randomNumber){
        tries++;
        long endTime = System.currentTimeMillis();
        long gameTime = endTime - startTime;
        System.out.println("Well done! You won the game in " + tries + " guesses " + "and " + gameTime/1000 +  " seconds!");
        System.out.println("Please enter your name: ");
        playerName = input.nextLine();
        }


}
}

Answer 1

更改 while 循环，以便它检查当前猜测的值是否为"退出"。这样，当给出 quit 命令时，它将停止循环，例如

while(guess!=randomNumber && !currentGuess.equalsIgnoreCase(quit))

Answer 2

放在一个（或所有 if ）中 while 里面

if (currentGuess.equals("quit") {
   playGame = false
}

并将 while 更改为：

while (guess!=randomNumber && playGame)

Answer 3

答案如下：全局布尔变量：

bool userWantsToQuit = false;

因此，如果有人键入int quit（不应该是"quit"，因为它是字符串吗？

if (currentGuess.equalsIgnoreCase(quit)) 
{
    userWantsToQuit = true; // we mark that someone wants to quit
    System.out.println("Thanx for playing"); // we output message
    continue; // skip execution of the rest (or you could use else if)
}

在底部，您可以更改 while 语句以停止游戏，如果用户想要退出为真：

(guess!=randomNumber && !userWantsToQuit)

我已经很久没有使用java了，我没有测试它，但它绝对是好的方向。