使用RouteatTribute时无法提交表格，因此提交错误的诉讼

Question

这是我的控制器操作：

httpget

// GET: ControllerName/Create
[Route("CreateDocument/{personId}")]
public ActionResult Create(int personId)
{
    var personDocumentation = new PersonDocumentation()
    {
        PersonId = pilotId
    };
    ViewBag.DocumentationTypeIdSelection = new SelectList(db.DocumentationTypes, "Id", "DocumentationTypeName");
    return View(personDocumentation);
}

httppost

[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Create([Bind(Include = "Id,PersonId,DateReceived,DocumentationTypeId,Filepath")] PersonDocumentation personDocumentation)
{
    if (ModelState.IsValid)
    {
        if (Request.Files.Count > 0)
        {
            // performing stuff here
        }
        db.PersonDocumentations.Add(personDocumentation);
        db.SaveChanges();
        return RedirectToAction("Index", "PersonDocumentations", new {pilotId = personDocumentation.PilotId});
    }
    ViewBag.DocumentationTypeId = new SelectList(db.DocumentationTypes, "Id", "DocumentationTypeName", personDocumentation.DocumentationTypeId);
    return View(personDocumentation);
}

view/form

@using (Html.BeginForm("Create", "PersonDocumentations", FormMethod.Post, new {enctype = "multipart/form-data" }))
{
    // Form stuff here
    <div class="form-group">
        <input type="submit" value="Create" class="btn btn-lg btn-success" />
    </div>
}

调试时，提交时，我将被重定向到使用路由属性的HTTPGET创建动作。当相应的获取操作具有路由属性时，我可以提交邮局吗？

update

在下面看nkosi回答后。我有：

[HttpGet]
[Route("CreateDocument/{personId}")]
public ActionResult Create(int personId)
{
    // stuff here
}
[HttpPost]
[Route("CreateDocument")]
[ValidateAntiForgeryToken]
public ActionResult Create([Bind(Include = "Id,PersonId,DateReceived,DocumentationTypeId,Filepath")] PersonDocumentation personDocumentation)
{
    // stuff here
}

在我的查看页面上..要获取httpget操作，我有一个按钮链接：

@Html.ActionLink("Create New Documentation", "Create", new {personId = Model.PersonId}, new {@class = "btn btn-info"})

但是，当我悬停在按钮上时，我会在左下角看到链接：

http://localhost:xxxxx/CreateDocument?personId=4

不应该：

http://localhost:xxxxx/CreateDocument/4

当我从HTTPPOST动作中删除路由属性时，左下角的URL显示为http://localhost:xxxxx/CreateDocument/4

然后，当我单击按钮时，我会收到404个错误：

Requested Url:  /CreateDocument

public class RouteConfig
{
    public static void RegisterRoutes(RouteCollection routes)
    {
        routes.IgnoreRoute("{resource}.axd/{*pathInfo}");
        routes.MapMvcAttributeRoutes();
        routes.MapRoute(
            name: "Default",
            url: "{controller}/{action}/{id}",
            defaults: new { controller = "PersonInfo", action = "Index", id = UrlParameter.Optional }
        );
    }
}

Answer 1

您正在混合属性和基于约定的路由。

如果在控制器上使用属性路由，则需要全部进入。当使用多个操作时，您还必须包括[Http{Verb}]来进一步区分动作路由。

public class PersonDocumentationsController : Controller {
    [HttpGet]
    public ActionResult Index() {
        //...
    }
    //GET CreateDocument/4
    [HttpGet]
    [Route("CreateDocument/{personId:int}")]
    public ActionResult Create(int personId) {
        //...
    }
    //POST CreateDocument/4
    [HttpPost]
    [Route("CreateDocument/{personId:int}")]
    [ValidateAntiForgeryToken]
    public ActionResult Create([Bind(Include = "Id,PersonId,DateReceived,DocumentationTypeId,Filepath")] PersonDocumentation personDocumentation) {
        //...
    }
}

这也假定对控制器没有RoutePrefix。

现在，当您致电

时

@Html.BeginForm("Create", "PersonDocumentations", FormMethod.Post, new {enctype = "multipart/form-data" }))

在PersonDocumentationsController.Create视图中，它将映射到正确的操作。

POST CreateDocument/4

对于动作链接，您还需要包括所需的控制器

@Html.ActionLink("Create New Documentation", "Create", "PersonDocumentations" , new {personId = Model.PersonId}, new {@class = "btn btn-info"})

应该映射到

GET http://localhost:xxxxx/CreateDocument/4

ASP.NET MVC 5