>我正在寻找我已编程到代码中的分割错误。当我的函数parseRecord(string)
生成一个向量并且我想打印出其中一个元素时,它基本上会出现。我已经缩小了范围,但找不到错误。向量是 Record 对象,这些对象是通过读取文件创建的,该文件每行有一行数据。
类的对象(不创建向量(时,我都可以很好地打印元素。它仅在我使用创建向量的 parseRecord(string( 函数时出现。
我还尝试在函数本身中打印它,结果相同。所以我认为这不是范围问题。
#include <iostream>
#include <fstream>
#include <iomanip>
#include <vector>
#include "record.hpp"
ifstream parsefile(string filename);
std::vector<Record> parseRecord(string line);
int main(int argc, char const *argv[])
{
std::vector<Record> dataSet = parseRecord("data.dat");
Record record("D11101001", "Max", "Muestermann",
10239, "fictionalmarkt.com", "23.12.19", "11:11:00");
cout << record;
for(std::vector<Record>::const_iterator i = dataSet.begin(); i != dataSet.end(); ++i){
cout << *i << endl;
}
return 0;
}
//METHOD-IMPLEMENTATION
//parse-file definition - Test if file is accessible
ifstream parsefile(string filename)
{
ifstream inFile(filename);
if (!inFile)
{
cerr << "File could not be opened" << endl;
exit(-1);
}
cout << "Input-file is readable!" << endl;
return inFile;
}
//parse-record definition - read file, add to vector<Record> and return vector
std::vector<Record> parseRecord(string filename)
{
vector<Record> dataSet;
ifstream inFile = parsefile(filename);
string line;
while (getline(inFile, line))
{
stringstream linestream(line);
string accountNb;
string firstName;
string lastName;
string amountStr; //format 100 = 1.00€
string merchant;
string date;
string time;
long double amount;
getline(linestream, accountNb, '|');
getline(linestream, firstName, '|');
getline(linestream, lastName, '|');
getline(linestream, amountStr, '|');
getline(linestream, merchant, '|');
getline(linestream, date, '|');
getline(linestream, time, 'n');
try
{
amount = stold(amountStr);
}
catch (const std::exception &e)
{
std::cerr << e.what() << 'n'
<< "Conversion error";
}
amount *= 100.0; //to correct the decimal format
Record recordEntry(accountNb, firstName, lastName, amount, merchant, date, time);
//cout << recordEntry << endl;
dataSet.push_back(recordEntry);
}
return dataSet;
}
记录.hpp
class Record
{
private:
string accountNb;
string firstName;
string lastName;
long double amount; //format 100 = 1.00€
string merchant;
string date;
string time;
public:
Record(string, string, string, long double, string, string, string);
~Record();
friend ostream& operator<<(ostream&, const Record&);
};
记录.cpp
#include "record.hpp"
#include <ostream>
Record::Record(string accountNb, string firstName, string lastName,
long double amount, string merchant, string date, string time)
{
this->accountNb = accountNb;
this->firstName = firstName;
this->lastName = lastName;
this->amount = amount;
this->merchant = merchant;
this->date = date;
this->time = time;
}
Record::~Record()
{
}
ostream &operator<<(ostream &os, const Record &rec)
{
os << right;
os << setw(15) << "Account Nb:" << setw(50) << rec.getAccountNb() << endl;
os << setw(15) << "First Name:" << setw(50) << rec.getFirstName() << endl;
os << setw(15) << "Last Name:" << setw(50) << rec.getLastName() << endl;
try
{
os << showbase;
os << setw(15) << "Amount:" << setw(50);
os.imbue(std::locale("de_DE.UTF-8"));
os << put_money(rec.getAmount(), true) << endl;
}
catch (const std::exception &e)
{
std::cerr << e.what() << "locale not supported system";
}
os << setw(15) << "Merchant:" << setw(50) << rec.getMerchant() << endl;
os << setw(15) << "Date:" << setw(50) << rec.getDate() << endl;
os << setw(15) << "Time:" << setw(50) << rec.getTime() << endl;
}
因此,控制台将打印:
Account Nb: D11101001
First Name: Max
Last Name: Muestermann
Amount: 102,39 EUR
First Name: Jonny
Last Name: Doe
Amount: 80,38 EUR
Merchant: markt.de
Date: 25.12.19
Time: 11:11:19
Segmentation fault (core dumped)
所以它在第一行之后退出。
一个错误是你没有从这个函数返回一个值:
ostream &operator<<(ostream &os, const Record &rec)
不从声明为返回值的函数返回值是未定义的行为。
ostream &operator<<(ostream &os, const Record &rec)
{
//...
return os; // <-- you are missing this line
}
以上是明显的错误,但另一个潜在的错误在您的有效double
测试中。 你捕获了一个异常,但随后你的代码继续,就好像double
是有效的,而实际上它是未初始化的。
double amount; // <--uninitialized.
//..
try
{
amount = stold(amountStr);
}
catch (const std::exception &e)
{
std::cerr << e.what() << 'n' << "Conversion error";
}
amount *= 100.0; // <-- behavior undefined if exception above this line was thrown.