将函数值作为浮点型 Python 3.6.1 返回

Question

我收到以下错误，似乎无法弄清楚如何解决。按照逻辑，我将 3 个函数和所有 3 个返回值调用为 float，然后对存储的返回值执行一些数学运算并将其打印为 float。那么哪里出了问题呢？我为 A 面输入 4，在 B 面输入 5。

错误消息：

输入A面长度：4.0 输入B面长度：5.0

Traceback (most recent call last):
File "python", line 26, in <module>
File "python", line 9, in main
File "python", line 24, in calculateHypotenuse
TypeError: unsupported operand type(s) for ^: 'float' and 'float'

---

import math
def main():
#Call get length functions to get lengths.
lengthAce = getLengthA()
lengthBee = getLengthB()
#Calculate the length of the hypotenuse
lengthHypotenuse = calculateHypotenuse(float(lengthAce),float(lengthBee))
#Display length of C (hypotenuse)
print()
print("The length of side C 'the hypotenuse' is {}".format(lengthHypotenuse))
#The getLengthA function prompts for and returns length of side A  
def getLengthA():
return float(input("Enter the length of side A: "))
#The getLengthA function prompts for and returns length of side B
def getLengthB():
return float(input("Enter the length of side B: "))
def calculateHypotenuse(a,b):
return math.sqrt(a^2 + b^2)
main()
print()
print('End of program!')

Answer 1

^

在Python中是按位XOR运算符，而不是幂运算符：

^ 运算符产生其参数的按位 XOR(独占 OR(，该参数必须是 intege

您需要改用**，即幂运算符：

def calculateHypotenuse(a,b):
return math.sqrt(a**2 + b**2)