在子项"发布"操作后返回右父项的"get"

Question

我在多个父操作中放置了相同的子操作，假设有两个父视图：

@model Parent1Model 
@{
ViewBag.Title = "Parent1";
Layout = "~/Views/Shared/_Layout.cshtml";
}
@Html.Action("Child","MainControler")

第二位家长：

@model Parent2Model
@{
ViewBag.Title = "Parent2";
Layout = "~/Views/Shared/_Layout.cshtml";
}
@Html.Action("Child","MainControler")

所有操作都放在同一个控制器中。

public ActionResult parent1() //GET
{
Parent1Model model = new Parent1Model()
return View(model );
}
public ActionResult parent2() //GET
{
Parent2Model model = new Parent2Model()
return View(model );
}
public ActionResult Child() //GET
{
ChildModel model = new ChildModel()
return View(model );
}
[HttpPost]
public ActionResult Child(ChildModel model) //POST
{
DoThingsWithResult(model)
// The next line should return the get of the parent action
return RedirectToParent() // This does not exist...
}

现在，我如何告诉孩子打电话给他右父母的GET？身为众多家长的孩子，他怎么知道这次是哪位家长叫的呢？

我找不到任何东西，无论是在谷歌上还是在"可能已经有你答案的问题"中。

Answer 1

你可以再添加一个参数来确定它来自哪里， 您还可以将此参数设置为字符串，该字符串将是父操作名称本身，并将该参数传递给您的RedirectToAction(param)

前任

[HttpPost]
public ActionResult Child(string ParentName, ChildModel model) //POST
{
DoThingsWithResult(model)
// The next line should return the get of the parent action
return RedirectToAction(ParentName) // This does not exist...
}

在父操作中

public ActionResult parent2() //GET
{
Parent2Model model = new Parent2Model();
ViewBag.Parent = "parent2";
return View(model );
}

在您看来

@model Parent2Model
@{
ViewBag.Title = "Parent2";
Layout = "~/Views/Shared/_Layout.cshtml";
}
@Html.Action("Child","MainControler", new {ParentName= ViewBag.Parent})

对父操作 1 执行相同的操作