如何创建一个检查网站可用性的python函数？

Question

我当前写的代码如下：

def Ws_availbality(url):
    check = print(urllib.request.urlopen("https://www.youtube.com/").getcode())
    if check == 200:
        print ("Website is running")
    else:
        print("The website is currently down")
Ws_availbality('https://www.youtube.com/')

---

问题是，尽管它返回200，但我无法获得执行if语句。它只是执行其他语句。我也可以接受不同的功能方法。

Answer 1

您必须将打印移动到其他地方：

def Ws_availbality(url):
    check = urllib.request.urlopen("https://www.youtube.com/").getcode()
    print(check)
    if check == 200:
        print ("Website is running")
    else:
        print("The website is currently down")
Ws_availbality('https://www.youtube.com/')