我想得到preg_replace如果替换,则显示结果,否则为空
<?php
$text = "text4 text1 text2 text3";
$replace = [
'/btext1b/' => 'replace1', //replace case sensitive
'/btext2b/i' => 'replace2', //non-sensitive
'/b(text3|text4)b/i' => 'replace3', //replace both text3 and text4
];
$result = preg_replace(array_keys($replace), $replace, $text);
echo $result;
结果 = 替换3 替换1 替换2 替换3
和
<?php
$text = "text4x text1x text2x text3x";
$replace = [
'/btext1b/' => 'replace1', //replace case sensitive
'/btext2b/i' => 'replace2', //non-sensitive
'/b(text3|text4)b/i' => 'replace3', //replace both text3 and text4
];
$result = preg_replace(array_keys($replace), $replace, $text);
echo $result;
结果 = 文本 4x 文本 1x 文本 2x 文本 3x
如果不替换任何东西,那么它显示原始$text,如果任何单词不替换,我想在那里显示空白结果
您可以使用 strcmp 来比较字符串。
strcmp($text,$result);//如果字符串相同,则返回 0
$compare = strcmp($text,$result);
if($compare == 0){ echo $text; }
else { echo 'Result not found'; }