我正在尝试对字节文件中存在的十六进制代码进行单词袋的自定义实现。因此，十六进制语料库将由"？？"这样的字符组成。 我找到了这段代码用于 Bow 的自定义实现，但它从语料库中删除了"？？"。
# Replace all none alphanumeric characters with spaces
s="0,1,2,3,4,5,6,7,8,9,0a,0b,0c,0d,0e,0f,10,11,12,13,14,15,16,17,18,19,1a,1b,1c,1d,1e,1f,20,21,22,23,24,25,26,27,28,29,2a,2b,2c,2d,2e,2f,30,31,32,33,34,35,36,37,38,39,3a,3b,3c,3d,3e,3f,40,41,42,43,44,45,46,47,48,49,4a,4b,4c,4d,4e,4f,50,51,52,53,54,55,56,57,58,59,5a,5b,5c,5d,5e,5f,60,61,62,63,64,65,66,67,68,69,6a,6b,6c,6d,6e,6f,70,71,72,73,74,75,76,77,78,79,7a,7b,7c,7d,7e,7f,80,81,82,83,84,85,86,87,88,89,8a,8b,8c,8d,8e,8f,90,91,92,93,94,95,96,97,98,99,9a,9b,9c,9d,9e,9f,a0,a1,a2,a3,a4,a5,a6,a7,a8,a9,aa,ab,ac,ad,ae,af,b0,b1,b2,b3,b4,b5,b6,b7,b8,b9,ba,bb,bc,bd,be,bf,c0,c1,c2,c3,c4,c5,c6,c7,c8,c9,ca,cb,cc,cd,ce,cf,d0,d1,d2,d3,d4,d5,d6,d7,d8,d9,da,db,dc,dd,de,df,e0,e1,e2,e3,e4,e5,e6,e7,e8,e9,ea,eb,ec,ed,ee,ef,f0,f1,f2,f3,f4,f5,f6,f7,f8,f9,fa,fb,fc,fd,fe,ff,??"
import re
def generate_ngrams(s, n):
# Convert to lowercases
s = s.lower()
s = re.sub(r'[^a-zA-Z0-9s]', ' ', s)
# Break sentence in the token, remove empty tokens
tokens = [token for token in s.split(" ") if token != ""]
# Use the zip function to help us generate n-grams
# Concatentate the tokens into ngrams and return
ngrams = zip(*[token[i:] for i in range(n)])
return [" ".join(ngram) for ngram in ngrams]
删除此行时：s = re.sub(r'[^a-zA-Z0-9s]', ' ', s)，它不返回任何内容
正则表达式用一个空格替换每个不是(a-z、A-Z、0-9、任何空格(的字符。这包括您要保留的?。将其添加到排除集
s = re.sub(r'[^a-zA-Z0-9s?]', ' ', s)
要使其正常工作(您还必须修复token中不可理解的错别字(。
如果删除正则表达式，它返回"nothing"的原因是因为它只在空格上拆分 - 原始字符串中没有空格 - 然后返回每对单词。你不能用一件物品做一对。