如何捕获填充编辑文本并按下新键时的事件?


<EditText
android:id="@+id/name"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:imeOptions="actionNext"
android:inputType="textNoSuggestions|textCapCharacters"
android:maxLength="3"
android:hint="ABC"
/>

还有另一个EditText,当所有 3 个符号都填写在name时,应该重点关注。

name.addTextChangedListener(object: TextWatcher {
override fun afterTextChanged(s: Editable?) {
// Move to surname when all three symbols are entered.
if (name.text.toString().length == 3) {
surname.requestFocus()
}
}
override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) { }
override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) { }
})

当我们输入 1、2 和 3 个符号时,它就会正常工作。但是当我们选择name中的最后一个位置时,按键盘中的新字母,没有任何反应。我试图抓住按键

name.setOnKeyListener { v, keyCode, event ->
if (name.text.getText().length == 3) {
surname.requestFocus()
}
false
}

但事件不会发生。如何移动焦点?

maxLength更改为 4

android:maxLength="4"

afterTextChanged

override fun afterTextChanged(s: Editable?) {
// Move to surname when all three symbols are entered.
if (name.isFocused() && name.text.toString().length > 3) {
surname.requestFocus();
name.setText(s.toString().substring(0,3));
}
}

在 beforeTextChanged(( 中添加一个检查,以确定字符序列的长度是否已经是 3 个字符,如果是这样,则请求关注姓氏

根据我@nupadhyaya回答。

1(删除android:maxLength="3"(或可以设置android:maxLength="4"(。

2( 为新交易品种添加了事件:

name.addTextChangedListener(object: TextWatcher {
override fun afterTextChanged(s: Editable?) {
val text = name.text.toString()
if (text.length >= 3) {
surname.requestFocus()
if (text.length > 3) {
// Remove symbols after third.
name.setText(text.substring(0, 3))
}
}
override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) { }
override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) { }
})
}

3(添加了姓氏Backspace键的事件:

surname.setOnKeyListener { _, keyCode, _ ->
if (keyCode == KeyEvent.KEYCODE_DEL && surname.text.toString().isEmpty()) {
// Move to the last symbol of name.
name.requestFocus()
name.setSelection(name.text.toString().length)
}
false
}

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