我有一本结构如下的字典,
arrayOne = {
"2015-11-09T00:00:00.000Z" = 1;
"2015-11-16T00:00:00.000Z" = 2;
"2015-11-23T00:00:00.000Z" = 3;
"2015-11-30T00:00:00.000Z" = 4;
"2015-12-07T00:00:00.000Z" = 5;
"2015-12-14T00:00:00.000Z" = 6;
"2015-12-21T00:00:00.000Z" = 7;
"2015-12-28T00:00:00.000Z" = 8;
"2016-01-04T00:00:00.000Z" = 9;
"2016-01-11T00:00:00.000Z" = 1;
"2016-01-18T00:00:00.000Z" = 2;
"2016-01-25T00:00:00.000Z" = 3;
}
我想创建另一个字典,其值如下,
arrayTWo = {
"November" = 10;
"December" = 26;
"January" = 15;
}
我尝试在单独的数组中获取日期的月份值,在单独的数组中获取值,然后尝试在 nsmutabledictionary 中获取这些值,但它没有为重复键分配值并得到了这样的解决方案
arrayTWo = {
"November" = 4;
"December" = 8;
"January" = 3;
}
我找不到更好的方法,任何选择都值得赞赏。谢谢。
试试这个,它使用NSDateFormatter
从日期获取月份名称,它根据当前区域设置进行本地化。如果您的区域设置不是英语,并且您需要获取英语月份名称,请取消注释该行以显式设置区域设置。
逻辑很简单:
枚举字典,如果键(月)存在,则添加值(如果未创建键)
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
formatter.dateFormat = @"MMMM";
// formatter.locale = [NSLocale localeWithLocaleIdentifier:@"en_US_POSIX"];
NSMutableDictionary *result = [NSMutableDictionary dictionary];
for (NSDate *key in arrayOne.allKeys) {
NSString *month = [formatter stringFromDate:key];
if (result[month] == nil) {
result[month] = arrayOne[key];
} else {
NSInteger value = [result[month] integerValue];
result[month] = @(value + [arrayOne[key] integerValue]);
}
}
NSLog(@"%@", result);