设置分页条件

Question

我正在尝试在 CakePHP 上做自定义分页，问题是我想传递自定义条件，如下所示：

$conditions['People'] = $this->People->find('all',
    array(
        'order' => array('People.id DESC'),
        'limit' => 16, 
        'order' => 'People.id DESC'
    )
);
$people = $this->paginate('People',$conditions);

这基本上是所有涉及分页的代码，但它不起作用，它抛出它找不到列 People...

我只想使用自定义条件进行分页，也就是说，我想事先设置条件，有没有办法做到这一点？

Answer 1

你看过文档吗？

根据文档，您应该添加如下条件：

public function list_recipes() {
    $this->Paginator->settings = array(
        'conditions' => array('Recipe.title LIKE' => 'a%'),
        'limit' => 10
    );
    $data = $this->Paginator->paginate('Recipe');
    $this->set(compact('data'));
}

所以猜测这应该有效：

public function list_people() {
    $this->Paginator->settings = array('order' => array('People.id DESC'),'limit' => 16,'order' => 'People.id DESC');
    $data = $this->Paginator->paginate('People');
    $this->set(compact('data'));
}

Answer 2

这是我在蛋糕 2.x 中的做法

首先，请确保在控制器中包含分页器组件和辅助程序，例如

$public $components = array(
  'Paginator'
);
$public $helpers = array(
  'Paginator'
);

然后在你的行动中

$options = array(
    'conditions' => array(
        'Post.status' => 1
    ),
    'fields' => array(
        'Post.id',
        'Post.title',
        'Post.created'
    ),
    'order' => array(
        'Post.created' => 'DESC'
    ),
    'limit' => 10
);
$this->Paginator->settings = $options;
$posts = $this->Paginator->paginate('Post');

Answer 3

好的，我解决了它，这就是我所做的：首先我声明分页，如果需要，它可以是空的：

public $paginate = array('People'=>array(
        'limit' => 6,
        'order' => 'People.id DESC'
    )); 

然后，每当我想改变一些东西时，我就会做：

$this->paginate['People']['limit'] = 12;