python传递参数模块

Question

我似乎无法理解这一点，我只是不了解如何在模块之间传递参数。当然，这对我来说似乎很简单，但也许我只是不明白，我对python很陌生，但确实有编程经验。

def main():
  weight = input("Enter package weight: ")
  return weight
def CalcAndDisplayShipping(weight):
  UNDER_SIX = 1.1
  TWO_TO_SIX = 2.2
  SIX_TO_TEN = 3.7
  OVER_TEN = 3.8
  shipping = 0.0
  if weight > 10:
    shipping = weight * OVER_TEN
  elif weight > 6:
    shipping = weight * SIX_TO_TEN
  elif weight > 2:
    shipping = weight * TWO_TO_SIX
  else:
    shipping = weight * UNDER_SIX
  print ("Shipping Charge: $", shipping)

main(CalcAndDisplayShipping)

当我运行这个时，我得到：输入包重量：（num）类型错误：无序类型：function（）>int（）

有人能向我解释一下吗？

Answer 1

有一点是在python中不需要main。另一种方法是这样做。

你真的需要主菜吗？

import os

def CalcAndDisplayShipping(weight):
   UNDER_SIX = 1.1
   TWO_TO_SIX = 2.2
   SIX_TO_TEN = 3.7
   OVER_TEN = 3.8
   shipping = 0.0
   if weight > 10:
      shipping = weight * OVER_TEN
   elif weight > 6:
      shipping = weight * SIX_TO_TEN
   elif weight > 2:
      shipping = weight * TWO_TO_SIX
   else:
      shipping = weight * UNDER_SIX
   print ("Shipping Charge: $", shipping)
weight = float(input("Enter package weight: "))
CalcAndDisplayShipping(weight)

Answer 2

我认为你的意思是：

CalcAndDisplayShipping(main())

这将调用main()并将其返回值作为参数传递给CalcAndDisplayShipping()。

Answer 3

def CalcAndDisplayShipping(weight):
    UNDER_SIX = 1.1
    TWO_TO_SIX = 2.2
    SIX_TO_TEN = 3.7
    OVER_TEN = 3.8
    shipping = 0.0
    if weight > 10:
        shipping = weight * OVER_TEN
    elif weight > 6:
        shipping = weight * SIX_TO_TEN
    elif weight > 2:
       shipping = weight * TWO_TO_SIX
    else:
       shipping = weight * UNDER_SIX
    print ("Shipping Charge: $", shipping)
if __name__ == '__main__':
    weight = float(input("Enter package weight: "))
    CalcAndDisplayShipping(weight)

如果您使用python解释器运行此脚本，如python script_name.py、__name__变量值将为'__main__'。

如果您要将此模块导入其他一些模块，则__name__将不是__main__，也不会执行主部分。

因此，如果您想在将此模块作为单独的脚本运行时执行任何操作，则可以使用此功能。

只有当您将模块作为单独的脚本运行时，这个"if条件"才满足。