请求标头的 Web 异常返回状态代码说明，但不返回错误

Question

我们有兴趣捕获status code + status code description，它描述了在用户遇到连接错误时捕获异常时的错误。此方法在消息框中打印出该事件中的 Web 异常（此处未显示）。

为什么它不显示状态代码？

internal static List<string> getHeaders(string url, string postdata)
        {
            List<string> headers = new List<string>();
            try
            {
                ASCIIEncoding encoding = new ASCIIEncoding();
                byte[] byte1 = encoding.GetBytes(postdata);
                HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
                request.Timeout = 20000;
                request.AllowAutoRedirect = false;
                request.Method = "POST";
                request.ContentType = "application/x-www-form-urlencoded";
                request.ContentLength = byte1.Length;
                request.CookieContainer = new CookieContainer();
                request.Credentials = CredentialCache.DefaultCredentials;
                Stream newstream = request.GetRequestStream();
                newstream.Write(byte1, 0, byte1.Length);
                WebResponse response = request.GetResponse();
                HttpWebResponse httpresponse = (HttpWebResponse)response;
                headers.Add("Status Code: " + (int)httpresponse.StatusCode);
                headers.Add("Status Desc: " + httpresponse.StatusDescription);
                foreach (string key in response.Headers.Keys)
                {
                    if (!key.ToString().Equals("Location"))
                    {
                        var value = httpresponse.Headers[key];
                        headers.Add(key + ": " + value);
                    }
                }
                return headers;
            }
            catch (Exception ex)
            {
                headers.Add("ERROR MESSAGE: " + ex.Message);
                return headers;
            }
        }

这是对这个线程的引用，它在try-catching标头时向我们显示状态代码和状态代码描述。

Answer 1

没

关系，代码似乎工作正常。但是，返回的错误the remote name could not be resolved不会返回状态代码。