是否有办法从包含学生记录但由不同字符分隔的文件中读取?我的文字如下:
125 {John_BROWN_Biology} {100_81}
245 {Amanda_SMITH_Chemistry} {83_74}
436 {Michael_CLARK_Calculus} {35_48}
我必须将它们存储在单独的数组中,这样我才能计算它们的平均值并按升序排列。我用c++编写了如下代码:
int rank;
char st_info[SIZE];
int grades[SIZE];
bool success1 = false;
bool success2 = false;
bool success3 = false;
ifstream inFile;
inFile.open("records.txt");
string line;
int i=0, j=0;
while (!inFile.getline(rank, 30, '{').eof){
inFile.getline(st_info, SIZE, '_');
inFile.getline(words_array, SIZE, '_');
}
while (!success1)
{
getline(inFile,Line,'{'); // get values for info array
stringstream iss1;
iss1 << Line; //Put the string into a stream
iss1 >> rank; //To send data as an int.
cout << "STUDENT NUMBER:" << rank << " ";
while (!success2){
// for the info in {} part
getline(inFile,Line,'_');
stringstream iss;
iss << Line;
iss >> st_info[i];
cout <<"STUDENT INFO:" << st_info[i] << " ";
i++;
if (getline(inFile,Line,'}')){
stringstream iss2;
iss2 << Line;
iss2 >> st_info[i];
cout << st_info[i] << " ";
i=0;
success2 = true;
}
}
getline(inFile,Line,'{');
stringstream iss3;
iss3 << Line;
iss3 >> grades[j];
cout << "GRADES: "<< grades[i] << " ";
j++;
while (!success3){
getline(inFile,Line,'_');
stringstream iss4;
iss4 << Line;
iss4 >> grades[j];
cout << grades[i] << " ";
j++;
if (getline(inFile,Line,'}')){
stringstream iss5;
iss5 << Line;
iss5 >> grades[j];
cout << grades[i] << " ";
j=0;
success3 = true;
}
}
}
然而,作为输出,我得到:
1 J 100
2 A 100
4 M 100
试图修复,但情况变得更糟。有人能帮忙吗?提前感谢。
你的方法和代码有几个问题:
-
istream::getline()
不能读取整数。它只能读入一个char数组。 -
eof
是函数而不是属性 - 混合
<<
>>
与stringstream
解析数据的方式不是最优的。 - 使用
>>st_info[i]
,您从stringstream中提取单个字符,这将覆盖现有信息。 - 当然还有其他问题。
getline()
的非成员变量来读取字符串,而不是字符数组(这使我免于考虑缓冲区溢出):
...
char delim;
int rank;
string names, grades;
string line;
while (getline(inFile, line)) // read line by line
{
stringstream sst{line}; // then parse the line using a string stream
sst>>rank; // read an integer
sst>>delim; // skip white and read a single char
if (delim!='{') {
cout<<"Error on line: { expected for name instead of "<<delim<<endl;
continue; // next line, please !!
}
getline(sst,names, '}'); // TO DO: error handling
sst>>delim;
if (delim!='{') {
cout<<"Error on line: { expected for grades instead of "<<delim<<endl;
continue; // next line, please !!
}
getline(sst,grades, '}'); // TO DO: additional error handling
cout << rank<<" "<<names<<" "<<grades<<endl; // temporary:
// TO DO: parse names and grades by using further stringstreams
}
在线演示请注意,我使用了一种简单的解析方法:读取一个字符并检查它是否匹配预期的开始字符,然后使用getline()
读取直到结束字符(后者被使用,但从字符串中排除)。这不允许在格式中嵌套{...}
。