我试图建立一个倒数计时器,对于每个计数,我都想播放一个声音。动画工作正常,但我想知道在序列中运行动画时是否可以播放声音。
法典:
Animated.sequence([
Animated.timing(this.state.moveY3, {
toValue: 50,
duration: 1000,
useNativeDrive: true,
easing: Easing.spring
}), // play sound
Animated.timing(this.state.moveY3, {
toValue: 100,
duration: 100,
useNativeDrive: true,
}),
Animated.timing(this.state.moveY2, {
toValue: 50,
duration: 1000,
useNativeDrive: true,
easing: Easing.spring
}), //play sound
Animated.timing(this.state.moveY2, {
toValue: 100,
duration: 500,
useNativeDrive: true,
}),
Animated.timing(this.state.moveY1, {
toValue: 50,
duration: 1000,
useNativeDrive: true,
easing: Easing.spring
}), // play sound
Animated.timing(this.state.moveY1, {
toValue: 100,
duration: 500,
useNativeDrive: true,
}),
]).start()
注意:我知道如何播放声音,我使用反应原生声音包,我只是对如何在每次计数时播放声音感到困惑。
在每个动画的start()
方法中,可以添加一个回调,该回调在动画完成后执行。因此,与其将所有动画都写成sequence
,不如将其分解为更小的部分,如下所示:
// Run animation
animation1.start(() => {
playSound1();
Animated.sequence([
animation2,
animation3,
]).start(() => {
playSound2();
Animated.sequence([
animation4,
animation5,
]).start(() => {
playSound3();
animation6.start();
})
})
});
// Move animations into variables so that the execution of the animation is more readable
const animation1 = Animated.timing(this.state.moveY3, {
toValue: 50,
duration: 1000,
useNativeDrive: true,
easing: Easing.spring
});
const animation2 = Animated.timing(this.state.moveY3, {
toValue: 100,
duration: 100,
useNativeDrive: true,
}),
const animation3 = Animated.timing(this.state.moveY2, {
toValue: 50,
duration: 1000,
useNativeDrive: true,
easing: Easing.spring
}),
...
通过将第一个位的一些内容移动到其他函数中,您可以减少一点嵌套并使其更具可读性......但它应该像那样工作。