尝试打开串行端口.收到错误 .导致错误的原因

Question

我正在使用单声道和C#打开计算机上的ttys2端口。我花了很多时间试图弄清楚为什么我无法打开我的串行端口。我终于包括了一个尝试捕获来帮助弄清楚。我是C#的新手..因此，任何指导都会有所帮助。

Button was just pushed .... Opening Port....
Error in Opening dev/ttys2
System.IO.IOException: No such file or directory
  at System.IO.Ports.SerialPortStream.ThrowIOException () [0x00012] in 
<f8255d9ef0594d18ae2c0d97286b9a80>:0 
at System.IO.Ports.SerialPortStream..ctor (System.String portName, 
System.Int32 baudRate, System.Int32 dataBits, System.IO.Ports.Parity 
 parity, System.IO.Ports.StopBits stopBits, System.Boolean dtrEnable, 
System.Boolean rtsEnable, System.IO.Ports.Handshake handshake, 
System.Int32 readTimeout, System.Int32 writeTimeout, System.Int32 readBufferSize, System.Int32 writeBufferSize) [0x0001e] in <f8255d9ef0594d18ae2c0d97286b9a80>:0 
   at (wrapper remoting-invoke-with-check) 
    System.IO.Ports.SerialPortStream:.ctor (string,int,int,System.IO.Ports.Parity,System.IO.Ports.StopBits,bool,bool,System.IO.Ports.Handshake,int,int,int,int)
  at System.IO.Ports.SerialPort.Open () [0x00078] in 
<f8255d9ef0594d18ae2c0d97286b9a80>:0 
  at (wrapper remoting-invoke-with-check) 
System.IO.Ports.SerialPort:Open ()
  at MonoSerial.Program.Main () [0x00089] in 
 <805ba7595bb8403d9fb17ebbff143c7f>:0 

这是我写的代码：

 Console.WriteLine("Button was just pushed .... Opening Port....");
        SerialPort Serial_tty = new SerialPort();
        string ttyname;
        ttyname = "dev/ttys2";

        Serial_tty.PortName = ttyname;            // assign the port name 
        Serial_tty.BaudRate = 9600;               // Baudrate = 9600bps
        Serial_tty.Parity   = Parity.None;        // Parity bits = none  
        Serial_tty.DataBits = 8;                  // No of Data bits = 8
        Serial_tty.StopBits = StopBits.One;       // No of Stop bits = 1
        Serial_tty.Handshake = Handshake.None;
 try
 {
    Serial_tty.Open();                 // Open the port     
    Serial_tty.Write("A");             // Write an ascii "A"
    Serial_tty.Close();                // Close port
    Console.WriteLine("nA written to port {0}", Serial_tty.PortName);
 }
 catch(Exception e)
 {
   Console.WriteLine("Error in Opening {0}",Serial_tty.PortName);
   Console.WriteLine(e);
 }

Answer 1

ttyname = "dev/ttys2"

我很确定您需要在该文件名的前面有一个前导/，否则它将尝试相对于当前目录打开文件，例如 home/pax/dev/ttys2 .