我是 Django 的初学者，在 urls.py 中面临语法错误

Question

这是我的个人/网址.py。我已经尝试解决这个问题好几天了。我知道这一定是一个非常愚蠢的错误，但将不胜感激。

from django.conf.urls import url, include
from . import views
urlpatterns = [
url(r'^$',views.index, name='index'),
url(r'contact/',views.contact, name='contact')
url(r'about/',views.about, name='about')
]

这是views.py

def index(request):
return render(request, 'personal/home.html')
def contact(request):
return render(request, 'personal/basic.html', {'content':['https://www.facebook.com/arjunkashyap30']})
def about(request):
return render(request, 'personal/about.html', {'content': ["This is an abut 
page"]})

Answer 1

您忘记了定义的每个端点末尾的comma。

urlpatterns = [
url(r'^$',views.index, name='index'),
url(r'contact/',views.contact, name='contact'),
url(r'about/',views.about, name='about'),
]