属性错误:'property'对象没有属性'copy' - 尝试在 Django Rest 中获取对象列表时



为了练习我的Django技能,我尝试制作一个简单的模块,它应该或多或少像Django中的Admin站点一样工作。它应该从应用程序中收集所有模型,列出它们,并显示每个模型中的每个对象。我尝试使用Django Rest Framework。

这是我的观点。我有两种观点。api_root侦听所有模型,但也将参数models_name发送到另一个视图"model_view"。ModelViewSet应列出特定模型中的所有对象。

class ModelsViewSet(viewsets.ModelViewSet):
def get_serializer(self, *args, **kwargs):
serializer_name = '{model_name}Serializer'.format(
model_name=self.kwargs.get('name').split(".")[1]
)
return getattr(serializers, serializer_name)
def get_model(self):
"""methods return model based on name kwargs
:return:
"""
return apps.get_model(self.kwargs.get('name'))
def get_queryset(self):
return self.get_model().objects.all()
def get_object(self):
return self.get_model().objects.get(pk=self.kwargs.get('pk'))

@api_view(['GET'])
def api_root(request, format=None):
return Response([reverse(
viewname='model_view',
kwargs={'name': i._meta.label}) for i in apps.get_models()])

这是我的serializers.py。在这个文件中,序列化程序类是动态构建的。每个类都是基于django.apps.中的模型构建的

from django.apps import apps
from rest_framework import serializers
from admin_site import serializers as m
from . import models

app_models = apps.get_models()
for item in app_models:
name = "{}Serializer".format(item.__name__)
class Meta(type):
model = item
fields = '__all__'
m.__dict__[name] = type(name, (serializers.ModelSerializer,), {})
m.__dict__[name].__metaclass__ = Meta

最后是我的my_app.urls.py文件。我认为问题可能是ModelSetView没有使用DefaultRouter()注册,但另一方面,我需要将param传递给urlparn。我不知道

urlpatterns = [
url(r'^$', views.api_root),
url(r'^model/(?P<name>[w-.]+)/$',
views.ModelsViewSet.as_view({'get': 'list', 'put':'update'}), name='model_view'),
url(r'^api-auth/', include('rest_framework.urls', namespace='rest_framework'))

]

当我在api_root上时,一切都很好,我可以看到模型列表。但当我添加到根url/model/auth.User/i时,会出现以下错误:

Traceback (most recent call last):
File "/home/wojjak/Projects/envs/taskenvv/lib/python3.6/site-
packages/django/core/handlers/exception.py", line 41, in inner
response = get_response(request)
File "/home/wojjak/Projects/envs/taskenvv/lib/python3.6/site-
packages/django/core/handlers/base.py", line 217, in _get_response
response = self.process_exception_by_middleware(e, request)
File "/home/wojjak/Projects/envs/taskenvv/lib/python3.6/site-
packages/django/core/handlers/base.py", line 215, in _get_response
response = response.render()
File "/home/wojjak/Projects/envs/taskenvv/lib/python3.6/site-
packages/django/template/response.py", line 107, in render
self.content = self.rendered_content
File "/home/wojjak/Projects/envs/taskenvv/lib/python3.6/site-
packages/rest_framework/response.py", line 72, in rendered_content
ret = renderer.render(self.data, accepted_media_type, context)
File "/home/wojjak/Projects/envs/taskenvv/lib/python3.6/site-
packages/rest_framework/renderers.py", line 716, in render
context = self.get_context(data, accepted_media_type, 
renderer_context)
File "/home/wojjak/Projects/envs/taskenvv/lib/python3.6/site-
packages/rest_framework/renderers.py", line 650, in get_context
raw_data_put_form = self.get_raw_data_form(data, view, 'PUT', 
request)
File "/home/wojjak/Projects/envs/taskenvv/lib/python3.6/site-
packages/rest_framework/renderers.py", line 565, in get_raw_data_form
data = serializer.data.copy()
AttributeError: 'property' object has no attribute 'copy'

我能做些什么来完成任务并避免这个错误吗?

覆盖get_serializer_class()而非get_serializer()

相关内容

最新更新