我有两个字典数组:
Dict 1 =
[{"id":"100", "name":"Matt", "phone":"0404040404", "address":"TBC"}
,{"id":"110", "name":"Sean", "phone":"0404040404", "address":"TBC"}
, {"id":"120", "name":"Luke", "phone":"0404040404", "address":"TBC"}]
Dict 2 =
[{"id":"100", "address":"1 Main Street"}
,{"id":"110", "address":"2 Main Road"}
, {"id":"120", "address":"3 Main Street"}]
我想比较键:value对, id ,在dict 2中的每个字典cit dict 1中的每个字典,如果ID匹配,请在此中更新相应的地址。dict 1来自dict2中的值。
所以所需的输出应该是:
Dict 1 =
[{"id":"100", "name":"Matt", "phone":"0404040404", "address":"1 Main Street"}
,{"id":"110", "name":"Sean", "phone":"0404040404", "address":"2 Main Road"}
, {"id":"120", "name":"Luke", "phone":"0404040404", "address":"3 Main Street"}]
编辑
根据要求,这里是有关我如何解析数据的更多信息。我将dict1和dict2作为对http url call btw的响应。而且,我在解析时使用[字典]类型的字典。
let Task1 = URLSession.shared.dataTask(with: URL!) { (Data, response, error) in
if error != nil {
print(error)
} else {
if let DataContent = Data {
do {
let JSONresponse1 = try JSONSerialization.jsonObject(with: DataContent, options: JSONSerialization.ReadingOptions.mutableContainers)
print(JSONresponse1)
for item in JSONresponse1 as! [Dictionary<String, Any>] {
//Parse here
}
}
catch { }
DispatchQueue.main.async(execute: {
self.getAddressTask()
})
}
}
}
Task1.resume()
}
jsonresponse1是dict 1
然后在getAddressTask((func内部调用,我进行http url调用以获取dict 2
let AddressTask = URLSession.shared.dataTask(with: URL2!) { (Data, response, error) in
if error != nil {
print(error)
} else {
if let DataContent = Data {
do {
let JSONresponse2 = try JSONSerialization.jsonObject(with: timeRestrictionsDataContent, options: JSONSerialization.ReadingOptions.mutableContainers)
print(JSONresponse2)
for item in JSONresponse2 as! [Dictionary<String, Any>] {
//Parse here
}
catch { }
self.compileDictionaries()
}
}
}
AddressTask.resume()
jsonresponse2是dict2
compilecticationaries((我想获得如上图所示的所需输出。
您应该使用代码协议构建数据,并创建一种更新联系人的突变方法。如果您需要一旦更新了联系人的数组,则需要使用JSONENCODER编码您的联系人:
struct Contact: Codable, CustomStringConvertible {
let id: String
var address: String?
var name: String?
var phone: String?
mutating func update(with contact: Contact) {
address = contact.address ?? address
name = contact.name ?? name
phone = contact.phone ?? phone
}
var description: String {
return "ID: (id)nName: (name ?? "")nPhone: (phone ?? "")nAddress: (address ?? "")n"
}
}
游乐场测试:
let json1 = """
[{"id":"100", "name":"Matt", "phone":"0404040404", "address":"TBC"},
{"id":"110", "name":"Sean", "phone":"0404040404", "address":"TBC"},
{"id":"120", "name":"Luke", "phone":"0404040404", "address":"TBC"}]
"""
let json2 = """
[{"id":"100", "address":"1 Main Street"},
{"id":"110", "address":"2 Main Road"},
{"id":"120", "address":"3 Main Street"}]
"""
var contacts: [Contact] = []
var updates: [Contact] = []
do {
contacts = try JSONDecoder().decode([Contact].self, from: Data(json1.utf8))
updates = try JSONDecoder().decode([Contact].self, from: Data(json2.utf8))
for contact in updates {
if let index = contacts.index(where: {$0.id == contact.id}) {
contacts[index].update(with: contact)
} else {
contacts.append(contact)
}
}
let updatedJSON = try JSONEncoder().encode(contacts)
print(String(data: updatedJSON, encoding: .utf8) ?? "")
} catch {
print(error)
}
这将打印:
[{" id":" 100","电话":" 0404040404","名称":" Matt","地址":" 1 Main 街道"},{" id":" 110","电话":" 0404040404","名称":" sean","地址":" 2 主要的 路"},{" id":" 120","电话":" 0404040404","名称":" Luke","地址":" 3 大街"}]