MYSQL查询找出各种版本中的常见错误

Question

我有不同版本的一些错误的数据。我需要找出从旧版本传播的常见错误。在下面的数据示例中，我有兴趣了解此示例中的常见版本错误："这是一个 8.x 旧错误"，即数据中的最后 3 行

9.1.1.5   |xymodel1 |227501| This is a 9.x new bug 
8.1.2.9   |xymodel1 |227501| This a 8.x new bug 
8.1.1.5   |xymodel1 |227501| This a 8.x new1 bug 
7.1.2.30  |xy6700   |287640| This is a 7.x new bug
7.1.2.30  |xy6700   |288185| This is a 7.x new1 bug
9.1.1.5   |xymodel1 |227501| This is a 9.x new bug 
10.1.2.30 |xy6700   |288368| This is a 10.x new bug 
10.1.1.6  |xymodel1 |227501| This is a 10.x new bug 
8.1.1.5   |xymodel1 |227501| This is a 8.x old bug
9.1.1.5   |xymodel1 |227501| This is a 8.x old bug
10.1.1.5  |xymodel1 |227501| This is a 8.x old bug

我运行了以下查询，该查询应该为我提供了 8.x、9.x 和 10.x 中的常见错误，因为存在 AND 条件。 但是在我看到的结果中，其他伴随的行也很少，这在三个版本中并不常见。

select * from issue_table
where
bug_name in (select bug_name from issue_table where version like '8.%' and '9.%' and '10.%')

结果：结果中不应显示前两行，因为它们在各个版本中都不常见。

version   model     data    bug_name
8.1.2.9   xymodel1  227501  This a 8.x new bug
8.1.1.5   xymodel1  227501  This a 8.x new1 bug
8.1.1.5   xymodel1  227501  This is a 8.x old bug
9.1.1.5   xymodel1  227501  This is a 8.x old bug
10.1.1.5  xymodel1  227501  This is a 8.x old bug

我期待：

version   model     data    bug_name
8.1.1.5   xymodel1  227501  This is a 8.x old bug
9.1.1.5   xymodel1  227501  This is a 8.x old bug
10.1.1.5  xymodel1  227501  This is a 8.x old bug

SQL Fiddle链接可以在这里找到：https://www.db-fiddle.com/#&togetherjs=VTGbSRMgIO

你们能帮我编辑查询以选择所有三个版本中的常见错误吗？

Answer 1

这可能是您要查找的内容：

select * 
from issue_table
where bug_name in (
select bug_name 
from issue_table 
where version like '8.%' 
or version like '9.%' 
or version like '10.%' 
group by bug_name 
having count(*) = 3)

子选择计算所有三个版本中存在的错误。

您也可以将其编写为连接：

select it.* 
from (
select bug_name 
from issue_table 
where version like '8.%' 
or version like '9.%' 
or version like '10.%' 
group by bug_name 
having count(*) = 3
) tmp, issue_table it 
where it.bug_name = tmp.bug_name

Answer 2

您可以为每个可能的主要版本使用exists条件：

select i.*
from issue_table i
where
exists(select 1 from issue_table i1 where i1.bug_name = i.bug_name and i1.version like '8.%')
and exists(select 1 from issue_table i1 where i1.bug_name = i.bug_name and i1.version like '9.%')
and exists(select 1 from issue_table i1 where i1.bug_name = i.bug_name and i1.version like '10.%')

尽管这看起来有点冗长，但这应该是一个有效的选择，前提是您有一个索引(bug_name, version).

在您的数据库小提琴中，这将返回：

| version  | model    | data   | bug_name              |
| -------- | -------- | ------ | --------------------- |
| 8.1.1.5  | xymodel1 | 227501 | This is a 8.x old bug |
| 9.1.1.5  | xymodel1 | 227501 | This is a 8.x old bug |
| 10.1.1.5 | xymodel1 | 227501 | This is a 8.x old bug |