在提问之前，我想展示我的Python代码，我正在使用该代码读取Excel单元格，我正在绘制我想要的任何内容，并为arduino代码准备Excel单元格，以点亮32x92像素的塔。
import xlrd
ExcelFileName= 'data.xlsx'
workbook = xlrd.open_workbook(ExcelFileName)
worksheet = workbook.sheet_by_name("Sheet1")
#inside of the data.xlsx file I create 39 row and 31 column and this where I'm #drawing what I want to light up.
num_rows = worksheet.nrows #Number of Rows
num_cols = worksheet.ncols #Number of Columns
x=0 #for x line
y=0 #for y line
floors=-1
rooms=-1
def cell(y,x): #for getting values from each cells
return worksheet.cell_value(y, x) # Read the data in the current cell
#this is tower model and every floor has 92 addressable rgb leds.And there is 30 floors.Each 10 floor has different data cable so 1 data line controls 920 rgb.
#On arduino I have macro which is "#define LEDNO(FLOOR, ROOM) ((ROOM) + (FLOOR*92))" this.So if I write floor and room number I will get number of led.Because all strip connect to each other.
#First floor data connected from "right bottom corner",this is my start point for leds.And I'm reading excel cells so I have to start to reading from right bottom corner to have in order for my leds.
for i in range(30,20,-1):
y=i
floors+=1
for j in range(38,0,-1):
x=j
rooms+=1
if rooms>37:
rooms=0
print("leds[LEDNO(" + str(floors) + "," + str(rooms) +")].setRGB(" + str(cell(y,x)) + ");")
#for next 10 floor rooms should start from -1 again.
rooms=-1
for i in range(20,10,-1):
y=i
floors+=1
for j in range(38,0,-1):
x=j
rooms+=1
if rooms>37:
rooms=0
print("leds2[LEDNO(" + str(floors) + "," + str(rooms) +")].setRGB(" + str(cell(y,x)) + ");")
rooms=-1
for i in range(10,0,-1):
y=i
floors+=1
for j in range(38,0,-1):
x=j
rooms+=1
if rooms>37:
rooms=0
print("leds3[LEDNO(" + str(floors) + "," + str(rooms) +")].setRGB(" + str(cell(y,x)) + ");")
问题：如何使用Python从图像中获取RGB代码？有可能将这些RGB代码转换为30x92像素吗？至少我需要阅读和打印给定的图像像素。
我需要从图像中获得RGB颜色代码，就像我在excel上做的一样。我不知道Python是否可行。
您可能希望使用scipy以(30,92,3(numpy数组的形式读取图像(最后一个可能是4，取决于您没有显示的文件(，然后根据需要分配值：
img[i, j, :] = RGBvalue