无法在"节点"上执行'appendChild'：将 tr 追加到表时，参数 1 的类型不是"节点"错误

Question

我的代码如下:

  var counter = 3;
    function AddAddressRow() {
        var newRow = jQuery('<tr><td><div>' +
            '<select class="dropdown-wrap k-rtl " id="ddlPrefix' +
            counter +
            '_1" style="width: 100px;">' +
            '<option value="option1" selected="selected">Option 1</option>'+
            '<option value="option2">Option 2</option>' +
            '</select> <br /><br/></div></td><td><div>' +
            '<select class="dropdown-wrap k-rtl " id="ddlPrefix' +
            counter +
            '_2" style="width: 100px;">' +
            '<option value="option1" selected="selected">Option 1</option>'    +
            '<option value="option2">Option 2</option>' <
            +'/select><br /></div></td><td><input style="width: 100px;"           
            id="txtAddress' + counter+'"/><br/><br/></td></tr>');
        counter++;
        $("table#AddressTable").append(newRow);
    }

点击下面的按钮

 <button  onclick="AddAddressRow();">+</button>

I caught TypeError:

在'Node'上执行'appendChild'失败:参数1不是'Node'类型

Answer 1

newRow没有返回tr节点。查看此处

或者试试这样:

var tr_ele = document.createElement('tr');
tr_ele.innerHTML = '>html here..<';
$("table#AddressTable").append(tr_ele);