我有一小段代码会产生错误消息(我认为是因为数学公式)。有人知道为什么吗?
import matplotlib.pyplot as plt
import numpy as np
from scipy.optimize import curve_fit
from scipy.integrate import quad
n = 3
x = np.array([2.1,2.2,2.3,2.4])
y = np.array([0.9,2.1,3.2,17.9])
def func(x, a, b):
b1 = n*quad(x[n]*np.log(y[n]), 1, n) - quad(x[n], 1, n)*quad(np.log(y[n]), 1, n)
b2 = n*quad(x[n]**2, 1, n) - (quad(x[n], 1, n))**2
b = b1 / b2
a = np.exp(1/n+(quad(np.log(y[n]), 1, n) - b(quad(x[n], 1, n))))
return a*np.exp(b*x)
popt, pcov = curve_fit(func, x, y)
print popt
plt.plot(x, y)
plt.grid(True)
plt.show()
错误日志:
Traceback (most recent call last):
File "F:py-IATLaktat.py", line 20, in <module>
popt, pcov = curve_fit(func, x, y)
File "C:Python27libsite-packagesscipyoptimizeminpack.py", line 506, in curve_fit
res = leastsq(func, p0, args=args, full_output=1, **kw)
File "C:Python27libsite-packagesscipyoptimizeminpack.py", line 348, in leastsq
m = _check_func('leastsq', 'func', func, x0, args, n)[0]
File "C:Python27libsite-packagesscipyoptimizeminpack.py", line 14, in _check_func
res = atleast_1d(thefunc(*((x0[:numinputs],) + args)))
File "C:Python27libsite-packagesscipyoptimizeminpack.py", line 418, in _general_function
return function(xdata, *params) - ydata
File "F:py-IATLaktat.py", line 15, in func
b1 = n*quad(x[n]*np.log(y[n]), 1, n) - quad(x[n], 1, n)*quad(np.log(y[n]), 1, n)
File "C:Python27libsite-packagesscipyintegratequadpack.py", line 247, in quad
retval = _quad(func,a,b,args,full_output,epsabs,epsrel,limit,points)
File "C:Python27libsite-packagesscipyintegratequadpack.py", line 312, in _quad
return _quadpack._qagse(func,a,b,args,full_output,epsabs,epsrel,limit)
quadpack.error: quad: first argument is not callable
谢谢!
> 凯文指出,quad的第一个参数应该是一个函数,你输入了一个数字。我建议创建一个函数
def newfunc(x, y, n):
# Insert appropriate processing here
return x[n]*np.log(y[n])
现在将 newfunc 作为调用序列中具有适当 aguments 的 quad 的第一个参数。
请注意,对 quad 的其他调用也需要类似的修改。
根据文档,quad
的第一个参数应该是要集成的函数。您有一个表达式而不是函数。要解决此问题,您可以尝试在quad
调用中引入匿名函数:
b1 = n*quad(lambda n:x[n]*np.log(y[n]), 1, n) - quad(lambda n:x[n], 1, n) *
quad(lambda n:np.log(y[n]), 1, n)
这是未经测试的,但它应该有效。