我试图创建一副52张牌的4种花色:黑桃,红桃,梅花和方块。我试图在我的Deck类中创建这个for循环,但似乎遇到了一些关于实际让程序做我想做的事情的问题。我在想也许我可以做4个for循环,因为任务暗示,但是否有可能使用if/else-if来创建4套牌?
class Deck
{
private Card[] cards;
public Deck()
{
cards = new Card[52];
int check = 0;
for (int suitVal = 1; suitVal < 4; suitVal++)
{
for (int rankVal = 1; rankVal < 14; rankVal++)
{
if(suitVal == 1)
{
cards[check] = new Card(rankVal, "Spades");
}
else if (suitVal == 2)
{
cards[check] = new Card(rankVal, "Hearts");
}
else if (suitVal == 3)
{
cards[check] = new Card(rankVal, "Clubs");
}
else if (suitVal == 4)
{
cards[check] = new Card(rankVal, "Diamonds");
}
}
}
}
是有可能的。一共有13张牌和4种花色。我们的想法是,对于每种花色,你都要创建13张牌。伪代码和你已经得到的差不多:
for each of the four suits
loop 13 times for said suit
下面是你代码中的问题:
1-你的check
变量永远不会增加,所以你总是覆盖位置0的卡;它应该在每次插入卡片(内循环)后递增
2-你的外环只运行3次(i = 1, i = 2, i = 3),并且有4套。
如果你需要更多的帮助,请告诉我
你可以这样做:
class Deck
{
private Card[] cards;
public Deck()
{
cards =
new [] { "Spades", "Hearts", "Clubs", "Diamonds", }
.SelectMany(
suit => Enumerable.Range(1, 13),
(suit, rank) => new Card(rank, suit))
.ToArray();
}
}
或:
class Deck
{
private Card[] cards;
public Deck()
{
var query =
from suit in new [] { "Spades", "Hearts", "Clubs", "Diamonds", }
from rank in Enumerable.Range(1, 13)
select new Card(rank, suit);
cards = query.ToArray();
}
}
或:
class Deck
{
private Card[] cards;
public Deck()
{
cards = new Card[52];
var index = 0;
foreach (var suit in new [] { "Spades", "Hearts", "Clubs", "Diamonds", })
{
for (var rank = 1; rank <= 13; rank++)
{
cards[index++] = new Card(rank, suit);
}
}
}
}