我正在尝试列出特定id的所有类型:
{
"id": "/en/sony",
"type": [{
"name": "Topic",
"id": null
}]
}
此查询给出以下结果:http://tinyurl.com/lubavey
{
"result": {
"type": [
{
"id": "/common/topic",
"name": "Topic"
},
{
"id": "/base/audiobase/topic",
"name": "Topic"
},
{
"id": "/base/fblinux/topic",
"name": "Topic"
},
{
"id": "/base/digitalcameras/topic",
"name": "Topic"
},
{
"id": "/base/popstra/topic",
"name": "Topic"
},
{
"id": "/base/televisions/topic",
"name": "Topic"
},
{
"id": "/base/ps3games/topic",
"name": "Topic"
},
{
"id": "/base/filmcameras/topic",
"name": "Topic"
},
{
"id": "/m/04mny2g",
"name": "Topic"
}
],
"id": "/en/sony"
}
}
我想要完全相反的结果。我想要所有没有"主题"名称的类型。我怎样才能做到这一点?我试图使用属性为name
的!
运算符,这是MQL的参考指南中建议的,但它给了我错误:
"不能将不合格的属性名称与!reversing一起使用"。
我应该怎么做才能用!
消除这个错误,并获得相反的查询结果?
试用!=
:
{
"id": "/en/sony",
"type": [{
"name!=": "Topic",
"id": null
}]
}
!=运算符表示受约束的属性可以是指定的值。(它确实要求财产是某种东西,但是:它与属性为null的对象不匹配。)
点击此处了解有关!=
操作员的更多信息:http://wiki.freebase.com/wiki/MQL_operators#The_.22but_not.22_Operator_.21.3D