我是PHPUnit中嘲笑对象的新手,无法让它工作。我正在构建当前SensioGeneratorBundle
的扩展(用于Symfony2)。我使用通过PEAR
安装的PHPUnit 3.7。它运行在 PHP 5.3.5 上(因为 PEAR 安装在该版本中)。
我的剥离类是:
控制器生成器.php
class ControllerGenerator extends Generator
{
// ...
public function generate(BundleInterface $bundle, $controller, array $actions = array())
{
// ...
}
}
GenerateControllerCommand.php
class GenerateControllerCommand extends ContainerAwareCommand
{
private $generator;
/**
* @see Command
*/
public function configure()
{
// ...
}
public function execute(InputInterface $input, OutputInterface $output)
{
// ...
$generator = $this->generator;
$generator->generate($bundle, $controller);
// ...
}
protected function getGenerator()
{
if (null === $this->generator) {
$this->generator = new ControllerGenerator($this->getContainer()->get('filesystem'), __DIR__.'/../Resources/skeleton/bundle');
}
return $this->generator;
}
public function setGenerator(ControllerGenerator $generator)
{
$this->generator = $generator;
}
}
GenerateControllerCommandTest.php
class GenerateControllerCommandTest extends GenerateCommandTest
{
public function testNonInteractiveCommand()
{
$bundle = 'FooBarBundle';
$controller = 'PostController';
$input = array(
'command' => 'generate:controller',
'--bundle' => $bundle,
'--controller' => $controller,
);
$application = $this->getApplication();
$commandTester = $this->getCommandTester($input);
$generator = $this->getGenerator();
$generator
->expects($this->once())
->method('generate')
->with($this->getContainer()->get('kernel')->getBundle($bundle), $controller)
;
$commandTester->execute($input, array('interactive' => false));
}
protected function getCommandTester($input = '')
{
return new CommandTester($this->getCommand($input));
}
protected function getCommand($input = '')
{
return $this->getApplication($input)->find('generate:controller');
}
protected function getApplication($input = '')
{
$application = new Application();
$command = new GenerateControllerCommand();
$command->setContainer($this->getContainer());
$command->setHelperSet($this->getHelperSet($input));
$command->setGenerator($this->getGenerator());
$application->add($command);
return $application;
}
protected function getGenerator()
{
// get a noop generator
return $this
->getMockBuilder('SensioBundleGeneratorBundleGeneratorControllerGenerator')
->disableOriginalConstructor()
->setMethods(array('generate'))
->getMock()
;
}
}
当我运行PHPUnit时,我不断收到此错误:
$ phpunit TestsCommandGenerateControllerCommandTest
PHPUnit 3.7.0 by Sebastian Bergmann.
Configuration read from E:Wouterwebwampwwwwjsnipvendorsensiogenerator-bundleSensioBundleGeneratorBundlephpunit.xml.dist
F
Time: 2 seconds, Memory: 7.25Mb
There was 1 failure:
1) SensioBundleGeneratorBundleTestsCommandGenerateControllerCommandTest::testNonInteractiveCommand
Expectation failed for method name is equal to <string:generate> when invoked 1 time(s).
Method was expected to be called 1 times, actually called 0 times.
E:Wouterwebwampbinphpphp5.3.5PEARphpunit:46
FAILURES!
Tests: 1, Assertions: 7, Failures: 1.
为什么我会收到此错误?我想我在GenerateControllerCommand::execute
方法中调用了generate
命令?我做错了什么,可能是真的吗?或者这是PHPunit中的一个错误?
简而言之
生成两个不同的$generator
对象。呼叫发生在一个呼叫上,而另一个expect
它。
长
您更改了行为protected function getGenerator()
但原始函数期望调用该函数填充$this->generator
。
您的测试无法正常工作,并且该函数希望始终获得相同的生成器,并且在覆盖后,函数返回两个不同的对象。
您在一个对象上设置了预期的调用,并且调用发生在对象上。
只是看:
$generator = $this->getGenerator();
$generator
->expects($this->once())
->method('generate')
->with($this->getContainer()->get('kernel')->getBundle($bundle), $controller)
;
$commandTester->execute($input, array('interactive' => false));
}
$generator
变量不会放在任何地方的任何对象作用域中,因此不会对其进行调用,因为每次调用$this->getGenerator()
都会生成一个未存储在任何地方的新对象。
所以在
protected function getApplication() {
//...
$command->setGenerator($this->getGenerator());
//...
}
您的对象与测试用例中的对象不同。