乒乓球比赛



我正在为一个pygame中的一个桨乒乓球游戏编写代码,在该游戏中,球会从3堵墙中弹起,而桨板不在桨,这会让您失去生命。我的问题是,我无法弄清楚碰撞检测来实现此目的。这是我到目前为止所做的:

import pygame, sys
from pygame.locals import *
pygame.init()
screen_width = 640
screen_height = 480
Display = pygame.display.set_mode((screen_width, screen_height), 0, 32)
pygame.display.set_caption('Lonely Pong')
back = pygame.Surface((screen_width, screen_height))
background = back.convert()
background.fill((255, 255, 255))
paddle = pygame.Surface((80, 20))
_paddle = paddle.convert()
_paddle.fill((128, 0, 0))
ball = pygame.Surface((15, 15))
circle = pygame.draw.circle(ball, (0, 0, 0), (7, 7), 7)
_ball = ball.convert()
_ball.set_colorkey((0, 0, 0))
_paddle_x = (screen_width / 2) - 40
_paddle_y = screen_height - 20
_paddlemove = 0
_ball_x, _ball_y = 8, 8
speed_x, speed_y, speed_circle = 250, 250, 250
Lives = 5
clock = pygame.time.Clock()
font = pygame.font.SysFont("verdana", 20)
paddle_spd = 5
while True:
    for event in pygame.event.get():
        if event.type == QUIT:
            sys.exit()
        if event.type == KEYDOWN:
            if event.key == K_RIGHT:
                _paddlemove = paddle_spd
            elif event.key == K_LEFT:
                _paddlemove = -paddle_spd
        elif event.type == KEYUP:
            if event.key == K_RIGHT:
                _paddlemove = 0
            elif event.key == K_LEFT:
                _paddlemove = 0
    Livespr = font.render(str(Lives), True, (0, 0, 0))
    Display.blit(background, (0, 0))
    Display.blit(_paddle, (_paddle_x, _paddle_y))
    Display.blit(_ball, (_ball_x, _ball_y))
    Display.blit(Livespr, ((screen_width / 2), 5))
    _paddle_x += _paddlemove
    passed = clock.tick(30)
    sec = passed / 1000
    _ball_x += speed_x * sec
    _ball_y += speed_y * sec
    pygame.display.update()

我一直遇到的另一个问题是,当我启动它时,球根本没有出现。有人可以向我指出正确的方向吗?

首先,首先没有出现球,因为您没有填充表面,您正在设置color_key:

_ball.set_colorkey((0, 0, 0))

应该是

_ball.fill((0, 0, 0))

第二,为了检测碰撞,PyGame提供了一些功能,例如CollidePoint和Collidect。

https://www.pygame.org/docs/ref/rect.html#pygame.rect.colleidepoint

这意味着您需要表面的矩形。做到这一点:

my_surface.get_rect()

https://www.pygame.org/docs/ref/surface.html#pygame.surface.get_rect

为了与屏幕边缘碰撞,您可以随时进行

if _ball_x <= 0 or _ball_y <= 0 or _ball_x >= 640 or _ball_y >= 480:
    # collision detected

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