阿克曼函数尝试捕获问题

Question

i当前在做一个ackerman功能问题，我们必须在用户输入的故障安全中代码。因此，如果通常会导致程序崩溃的用户输入，则只需发送消息即可。我能够弄清楚整数值是否太大，但我无法弄清楚如何检查用户输入是否是整数。我尝试尝试使用" InputMismatchException"捕获块，但是代码开始弄乱和错误，或者只是不起作用。

public static void main(String[] args) {
//creates a scanner variable to hold the users answer
Scanner answer = new Scanner(System.in);

//asks the user for m value and assigns it to variable m
System.out.println("What number is m?");
int m = answer.nextInt();


//asks the user for n value and assigns it to variable n
System.out.println("What number is n?");
int n = answer.nextInt();

try{
//creates an object of the acker method
AckerFunction ackerObject = new AckerFunction();
//calls the method
System.out.println(ackerObject.acker(m, n));
}catch(StackOverflowError e){
    System.out.println("An error occured, try again!");
}

}

}

Answer 1

您必须放置

int n = answer.nextInt();

在尝试块中。然后，您可以捕获Java.util.inputMismatchException

这对我有用：

public static void main(String[] args) {
    //creates a scanner variable to hold the users answer
    Scanner answer = new Scanner(System.in);
    int m;
    int n;
    try{
        //asks the user for m value and assigns it to variable m
        System.out.println("What number is m?");
        m = answer.nextInt();
        //asks the user for n value and assigns it to variable n
        System.out.println("What number is n?");
        n = answer.nextInt();
    }catch(InputMismatchException e){
        System.out.println("An error occured, try again!");
    }
}