我想匹配两个表的 ID,然后如果 ID 匹配,则将其重定向到特定页面。
SELECT user_skill.user_id AS id_one, job_seeker.user_id AS id_two
FROM user_skill
INNER JOIN job_seeker ON (user_skill.user_id = job_seeker.user_id)
在下面使用此条件
if(mysqli_num_rows($result) > 0) {
while($fetch = mysqli_fetch_assoc($result)) {
if($fetch['id_one'] === $fetch['id_two']) {
header('location: userhome.php');
}
else {
header('location: userskill.php');
}
}
}
任何建议都会有所帮助。谢谢!!
SELECT user_skill.user_id AS id_one, job_seeker.user_id AS id_two
FROM user_skill
INNER JOIN job_seeker ON (user_skill.user_id = job_seeker.user_id)
在下面使用此条件
if(mysqli_num_rows($result) > 0) {
while($fetch = mysqli_fetch_assoc($result)) {
$variable=array($fetch['id_one']=>$fetch['id_two']);
foreach($variable as $x=$value)
{ if($x === $value( {
header('location: userhome.php');
}
else {
header('location: userskill.php');
}
}
}
}