弹簧启动mongoDB就像对数字字段的查询 - 整数/双精度

Question

我想在春季启动中对整数/双精度字段进行 LIKE 查询。
收藏名称 ： 玩家

{
    "firstName" : "Lionel",
    "lastName" : "messi",
    "team" : "FC Barcelona",
    "salary" : 40000,
    "type" : "football"
},{
    "firstName" : : "Cristiano",
    "lastName" : "Ronaldo",
    "team" : "Real Madrid C.F.",
    "salary" : 35000,
    "type" : "football"
},{
    "firstName" : : "Neymar",
    "lastName" : "Jr",
    "team" : "Paris Saint-Germain F.C.",
    "salary" : 25000,
    "type" : "football"
},{
    "firstName" : "Luis",
    "lastName" : "Alberto",
    "team" : "FC Barcelona",
    "salary" : 25000,
    "type" : "football"
},{
    "firstName" : "Virat",
    "lastName" : "Kohali",
    "team" : "Indian Cricket Team",
    "salary" : 40000,
    "type" : "cricket"
}

我的 Spring java 代码如下，生成查询。

String game = "football";
String team = "barcelona";
Double salary = 250;
Query query = new Query();
Set<String> gameType = new HashSet<>();
List<Criteria> andCriteria = new ArrayList<>();
gameType.add(game);
andCriteria.add(Criteria.where("type").in(gameType));
andCriteria.add(Criteria.where("team").regex(team,"i"));
Criteria[] criteriaArray = new Criteria[andCriteria.size()];
criteriaArray = andCriteria.toArray(criteriaArray);
query.addCriteria(new Criteria().andOperator(criteriaArray));
List<Players> players = mongoTemplate.find(query, Players.class);
return players;

查询：

db.players.find({
  $and: [{
      "type": {
        $in: ["football"]
        }
    },
    {
      "team": {
        $regex: "barcelona",
        $options: "i"
      }
    }]
})

上面的查询向我返回了 2 个"类型"为"足球"和"球队"的文档，如巴塞罗那

{"firstName" : "Lionel", "lastName" : "messi", "team" : "FC Barcelona", "salary" : 40000, "type" : "football"},
{"firstName" : "Luis", "lastName" : "Alberto", "team" : "FC Barcelona", "salary" : 25000, "type" : "football"}

但是我希望查询"类型"为"足球"和"薪水"，例如 250

db.players.find({
  $and: [{
      "type": {
        $in: ["football"]
      }
    },
    {
      $where : "/^250.*/.test(this.salary)"
    }]
})

返回的结果如下。

{"firstName" : : "Neymar", "lastName" : "Jr", "team" : "Paris Saint-Germain F.C.", "salary" : 25000, "type" : "football"},
{"firstName" : "Luis", "lastName" : "Alberto", "team" : "FC Barcelona", "salary" : 25000, "type" : "football"}

提前谢谢你。

Answer 1

我设法在双精度字段上构建了 LIKE 查询。

Query query = new Query();
Set<String> gameType = new HashSet<>();
List<Criteria> andCriteria = new ArrayList<>();
String game = "football";
int salary = 250;   
gameType.add(game);
andCriteria.add(Criteria.where("type").in(gameType));
andCriteria.add(Criteria.where("$where").is("/^" + salary + ".*/.test(this.salary)"));
Criteria[] criteriaArray = new Criteria[andCriteria.size()];
criteriaArray = andCriteria.toArray(criteriaArray);
query.addCriteria(new Criteria().andOperator(criteriaArray));
List<Players> players = mongoTemplate.find(query, Players.class);
return players;

正如我上面发布的那样，此代码片段生成 LIKE。
您也可以以简单的方式做到这一点。

Query query = new Query();
Set<String> gameType = new HashSet<>();
        
String game = "football";
int salary = 250;
        
gameType.add(game);
        
query.addCriteria(Criteria.where("type").in(gameType));
query.addCriteria(Criteria.where("$where").is("/^" + salary + ".*/.test(this.salary)"));
List<Players> players = mongoTemplate.find(query, Players.class);
return players; 

查询：

db.players.find({
  $and: [{
      "type": {
        $in: ["football"]
      }
    },
    {
      $where : "/^250.*/.test(this.salary)"
    }]
})     

我希望这会有所帮助。

Answer 2

基于@Rahul Ghadage的答案，我能够做到这一点：

query.addCriteria(Criteria.where("$where").is("/" + salary + "/.test(this.salary)"));

请注意，代码示例中的薪水是用要匹配的数字填充的 Java 变量。第二个薪水是 mongo 结构中的字段名称。

小心在 mongo 中使用带有用户输入的正则表达式！