当 EditText 输入为空时，Android 应用程序崩溃

Question

我正在尝试在 EditText 为空且单击按钮时显示 toast。

单击按钮时应用程序崩溃。

我可能做错了什么？请帮助我，因为我是移动应用程序开发的新手。 我需要在哪里进行更改或纠正什么才能完成此操作？任何帮助，不胜感激。

import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
import androidx.appcompat.app.AppCompatActivity;
public class EmployeeActivity extends AppCompatActivity {
EditText hourlyWage, totalRegularHours, totalOvertimeHours;
Button btnCalculate;
TextView result;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.employee_activity);
hourlyWage = findViewById(R.id.et_hourlyWage);
totalRegularHours = findViewById(R.id.et_totalRegularHours);
totalOvertimeHours = findViewById(R.id.et_totalOvertimeHours);
btnCalculate = findViewById(R.id.btnCalculate);
result = (TextView) findViewById(R.id.tv_Result);
}
// method to be called on onClick
public void calculateResult(View view) {
double regularHours = Integer.parseInt(totalRegularHours.getText().toString());
double overtimeHours;
overtimeHours = Integer.parseInt(totalOvertimeHours.getText().toString());
// check if EditText is empty
if (hourlyWage.getText().toString().trim().equals("")) {
Toast.makeText(this, "Please Enter The Value.", Toast.LENGTH_LONG).show();
}
// check if EditText is empty
else if (totalRegularHours.getText().toString().trim().equals("")) {
Toast.makeText(this, "Please Enter The Value.", Toast.LENGTH_LONG).show();
}
// check if EditText is out of range
else if (regularHours <= 0 && regularHours >= 40) {
Toast.makeText(this, "Please Enter The Value of Hours Between 0 to 40.", Toast.LENGTH_LONG).show();
}
// check if EditText is out of range
else if (overtimeHours <= 0 && overtimeHours >= 30) {
Toast.makeText(this, "Please Enter The Value of Hours Between 0 to 30.", Toast.LENGTH_LONG).show();
}
// calculates the answer
else if (regularHours >= 0 && regularHours <= 40) {
// formula for calculation
double regularWage;
regularWage = (Integer.parseInt(hourlyWage.getText().toString()) * Integer.parseInt(totalRegularHours.getText().toString())) + (Integer.parseInt(totalOvertimeHours.getText().toString()) * Integer.parseInt(hourlyWage.getText().toString()) * (1.5));
//displays the result in a TextView
result.setText(String.valueOf(regularWage));
}
}
}

Answer 1

您正在使用空字符串解析Integer.parseInt。此外，您正在以不同的类型 - 双精度存储整数。这是您的解决方法：

// method to be called on onClick
public void calculateResult(View view) {
// check if EditText is empty
if (hourlyWage.getText().toString().isEmpty()){
Toast.makeText(this, "Please Enter The Value.", Toast.LENGTH_LONG).show();
return;
}
// check if EditText is empty
if(totalRegularHours.getText().toString().isEmpty())
{
Toast.makeText(this, "Please Enter The Value.", Toast.LENGTH_LONG).show();
return;
}
int regularHours = Integer.parseInt(totalRegularHours.getText().toString());
int overtimeHours;
overtimeHours = Integer.parseInt(totalOvertimeHours.getText().toString());
// check if EditText is out of range
if (regularHours <= 0 && regularHours >= 40) {
Toast.makeText(this, "Please Enter The Value of Hours Between 0 to 40.", Toast.LENGTH_LONG).show();
}
// check if EditText is out of range
else if (overtimeHours <= 0 && overtimeHours >= 30) {
Toast.makeText(this, "Please Enter The Value of Hours Between 0 to 30.", Toast.LENGTH_LONG).show();
}
// calculates the answer
else if(regularHours >= 0 && regularHours <= 40) {
// formula for calculation
double regularWage;
regularWage = (Integer.parseInt(hourlyWage.getText().toString()) * Integer.parseInt(totalRegularHours.getText().toString())) + (Integer.parseInt(totalOvertimeHours.getText().toString()) * Integer.parseInt(hourlyWage.getText().toString()) * (1.5));
//displays the result in a TextView
result.setText(String.valueOf(regularWage));
}

}

Answer 2

您可以检查EditText是否为空或不使用该类TextUtils如下所示：

if(TextUtils.isEmpty(yourEditText.getText().toString())) {
Toast.makeText(this, "Edit text is empty", Toast.LENGTH_SHORT).show();
return;
}