如何修复 if 语句以处理字符串?

Question

我必须制作一个石头剪刀布游戏，但是当我尝试将输入转换为字符串时，if 语句不起作用str(.....)

我在这里使用了整数来确保代码在其他情况下正常工作，但它不适用于字符串。

我在运行此代码时也遇到使输入下划线的问题，如何做到这一点？

player_1 = str(input("Enter Player 1 choice (R, P, or S): "))
player_2 = str(input("Enter Player 2 choice (R, P, or S): "))

if player_1 == S and player_2 == S:
print("A tie!")
elif player_1 == R and player_2 == R:
print("A tie!")
elif player_1 == P and player_2 == P:
print("A tie!")
elif player_1 == R and player_2 == 2:
print("Rock beats scissors! Player 1 wins.")
elif player_1 == S and player_2 == R:
print("Rock beats scissors! Player 2 wins.")
elif player_1 == 9 and player_2 == R:
print("Paper beats rock! Player 1 wins.")
elif player_1 == R and player_2 == P:
print("Paper beats rock! Player 2 wins.")
elif player_1 == S and player_2 == P:
print("Scissors beat paper! player 1 wins.")
elif player_1 == P and player_2 == S:
print("Scissors beat paper! player 2 wins.")

每次运行代码时都会收到此错误：

Enter Player 1 choice (R, P, or S): S
Enter Player 2 choice (R, P, or S): S
Traceback (most recent call last):
File "D:CP 104**********srct03.py", line 16, in <module>
if player_1 == S and player_2 == S:
NameError: name 'S' is not defined

我做错了什么？

Answer 1

对于每种情况，您都是根据字符串检查变量的值。它们中的每一个的字符串可以是"R"、"S"或"P"，在你的 if 语句中，你应该这样写它们

例如

if player_1 == "S" and player_2 == "S":

等等。

正如@jedwards所说，您使用的是 python3，并且 input(( 返回一个字符串，因此不需要第一行和第二行中的 str(( 包装器

你可以简单地说

player_1 = input("Enter Player 1 choice (R, P, or S): ")
player_2 = input("Enter Player 1 choice (R, P, or S): ")