此代码的目的是在不进行任何身份验证的情况下获取ID和Pass，并在选中复选框时记住数据。我不明白为什么它不把数据保存到cookie中。
<?php
if(isset($_POST["chk"],$_POST["id"],$_POST["pass"])) {
$id=$_POST["id"];
$pwd=$_POST["pass"];
if (isset($_POST["chkbx"])){
setcookie("id","$id",time()+3600);
setcookie("pwd","$pwd",time()+3600);
$id=$_COOKIE["id"];
$pwd=$_COOKIE["pwd"];
}
print "Your ID " . $id;
print "Your PASS ". $pwd;
}
?>
<html>
<head>
<title>
Remember Me
</title>
</head>
<body>
Please Enter ID and PASS
<form method="post" >
Enter ID
<input type="text" name="id" />
Enter PASS
<input type="text" name="pass" />
<input type="submit" value="submit" /><br>
<input type="checkbox" name="chkbx" />Remember Me
<input type="hidden" name="chk" value="true" />
</form>
</body>
</html>
您的代码是正确的，但它需要清理
在这一部分中，我添加了一个条件来检查$_COOKIE中是否首先有任何内容在打印之前
if(isset($_COOKIE['id']) && isset($_COOKIE['pwd'])){
print "Your ID: " . $_COOKIE['id'] . '<br>';
print "Your PASS: ". $_COOKIE['pwd'] . '<br>';
}
你的代码会像这个
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST') {
$id = $_POST["id"];
$pwd = $_POST["pass"];
if (isset($_POST["chkbx"])){
setcookie("id", $id ,time()+3600);
setcookie("pwd", $pwd, time()+3600);
}
}
if(isset($_COOKIE['id']) && isset($_COOKIE['pwd'])){
print "Your ID: " . $_COOKIE['id'] . '<br>';
print "Your PASS: ". $_COOKIE['pwd'] . '<br>';
}
?>
<html>
<head>
<title>
Remember Me
</title>
</head>
<body>
Please Enter ID and PASS
<form method="post" >
Enter ID
<input type="text" name="id" value="<?= isset($_COOKIE['id'])? $_COOKIE['id']: '' ?>" />
Enter PASS
<input type="text" name="pass" value="<?= isset($_COOKIE['pwd'])? $_COOKIE['pwd']: '' ?>" />
<input type="submit" value="submit" /><br>
<input type="checkbox" name="chkbx" />Remember Me
<input type="hidden" name="chk" value="true" />
</form>
</body>
</html>