import java.awt.*;
import java.applet.*;
import java.awt.event.*;
public class MouseEvents extends Applet implements MouseListener, MouseMotionListener
{
String msg = ""; // I am not implementing those methods which
int mouseX = 0, mouseY = 0; // are not related to my question
public void init()
{
addMouseListener(this);
addMouseMotionListener(this);
}
public void mouseEntered(MouseEvent me)
{
mouseX = 0;
mouseY = 10;
msg = "Mouse Entered";
repaint();
}
public void mouseMoved(MouseEvent me)
{
mouseX = me.getX();
mouseY = me.getY();
showStatus("Moving mouse at "+mouseX+", "+mouseY);
}
public void paint(Graphics g)
{
g.drawString(msg, mouseX, mouseY);
}
}
我的小程序窗口的坐标:
左上角-(0,0(
左下角-(0199(
右上角-(349,0(
右下角-(349199(
我的期望:
当鼠标进入小程序窗口时,应在坐标
(0, 10)
处显示消息"Mouse Entered"
当鼠标移动时,状态窗口中应显示一条消息
"Moving mouse at mouseX, mouseY"
。其中mouseX
和mouseY
是鼠标的当前坐标
实际发生的情况:
消息"Mouse entered"
没有显示在坐标(0, 10)
处,而是显示在鼠标进入小程序窗口***的初始坐标处
例如,鼠标从Lower left corner
和Lower right corner
之间进入小程序窗口,例如(187, 199)
,则消息"Mouse Entered"
不是在(0, 10)
显示,而是在(187, 199)
显示
我的问题
尽管在mouseEntered()
中指定了mouseX = 0
和mouseY = 10
,为什么消息"Mouse Entered"
显示在鼠标进入小程序窗口的坐标处,而不是显示在坐标(0, 10)
处?
当您将鼠标移到查看窗格上时,查看窗格经常会被重新绘制。
您在此处覆盖mouseX
和mouseY
的值:
public void mouseMoved(MouseEvent me)
{
mouseX = me.getX();
mouseY = me.getY();
showStatus("Moving mouse at "+mouseX+", "+mouseY);
}
这会导致在移动鼠标时在这些坐标处进行重绘。如果您希望mouseEntered
不移动,可以使用本地变量,例如
public void mouseMoved(MouseEvent me)
{
int currentMouseX = me.getX();
int currentMouseY = me.getY();
showStatus("Moving mouse at "+currentMouseX+", "+currentMouseY);
}
public void mouseMoved(MouseEvent me)
{
mouseX = me.getX();
mouseY = me.getY();
showStatus("Moving mouse at "+mouseX+", "+mouseY);
}
每当您移动鼠标时,mouseMoved部分中的代码都会更新。因此,它显示mouseX和mouseY不是(0,10(的原因是因为您在mouseMoved方法中更改了mouseX的值和mouseY的值。使其显示鼠标最后位置的坐标。尝试创建一个不同的变量来跟踪鼠标的位置。