如何实现枚举嵌套类的函数?
class A(object):
class B(object):
pass
class C(object):
pass
def enumerate_nested_classes(_class):
return () # need proper implementation instead
assert set(enumerate_nested_classes(A)) == {A.B, A.C}
inspect.getmembers()
和inspect.isclass()
在这里应该有所帮助:
classes = [name for name, member_type in inspect.getmembers(A)
if inspect.isclass(member_type) and not name.startswith("__")]
print(classes) # prints ['B', 'C']
注意,需要not name.startswith("__")
检查来排除__class__
-我怀疑有一种更简单、更蟒蛇的方法可以做到这一点,如果有人能指出这一点的话,我将不胜感激
您可以使用下一个代码:
import types
class A(object):
class B(object):
pass
class C(object):
pass
def enumerate_nested_classes(_class):
return [getattr(_class, n) for n in dir(_class) if not n.startswith('__')
and isinstance(getattr(_class, n), (type, types.ClassType))]
assert enumerate_nested_classes(A) == [A.B, A.C]
print enumerate_nested_classes(A)
打印[<class '__main__.B'>, <class '__main__.C'>]
注:。dir(_class)
结果列表按字母顺序排序,因此在使用assert enumerate_nested_classes(A) == [A.B, A.C]
时,最好使用:assert sorted(enumerate_nested_classes(A)) == sorted([A.B, A.C])
。