警告:从不同大小的整数转换为指针[-Wint到指针转换]c编程

Question

我不明白为什么会触发此警告！

test.c:920:56:警告：从不同大小的整数转换到指针[-Wint到指针转换]

if（（memcpy（（void*）（buffer_post_offset+position），（void*）data_block_n，bytes_to_write））==NULL）｛

这是一段代码。。。

    char *buffer_post_offset = NULL;        
    // ....
    // Gets the data between offset and size        
    for(i = 0, data_block_n = start_at, position = 0, bytes_to_write = 0; data_block_n <= finish_at; ++data_block_n, ++i, position += bytes_to_write){
        // Gets from disk the sector/block of data
        if(Disk_Read(data_block_n, sector_str_data) == FAIL){
            osErrno = E_GENERAL;
            return FAIL;        
        }
        // Calculates how many bytes are to be written
        bytes_to_write = SECTOR_SIZE;
        if(data_block_n == finish_at)
            bytes_to_write -= inode.size - open_files_table.table[fd]->offset % SECTOR_SIZE;                 
        // Gets more memory for the buffer
        if((buffer_post_offset = (void *) realloc((void *) buffer_post_offset, (i + 1) * bytes_to_write * sizeof(char))) == NULL){
            osErrno = E_GENERAL;
            return FAIL;                        
        }
        // Writes into the buffer that store the data between offset and size
        // GETTING THE WARNING ON THE NEXT LINE !!!!!!
        if((memcpy((void *) buffer_post_offset + position, (void *) data_block_n, bytes_to_write)) == NULL){
            osErrno = E_GENERAL;
            return FAIL;        
        }
    }

Answer 1

sizeof (int)可能与sizeof(void*)不同，请使用std::uintptr_t在积分中保持指针。

Answer 2

在memcpy中，是sector_str_data，而不是data_block_n。

sector_str_data是char*，所以没有任何警告！

data_block_n是一个整数。

真的很抱歉！