如何将同一对象的列表解析为不同名称的 JSON

Question

我有一个对象Person这样的：

public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
    public string Address { get; set; }
}

我尝试创建这样的列表：

 var personList = new List<object>();
 personList.Add(new Person { Address = "addr1", Age = 20, Name = "Person1" });
 personList.Add(new Person { Address = "addr2", Age = 22, Name = "Person2" });
 personList.Add(new Person { Address = "addr3", Age = 25, Name = "Person1" });
 var jsonString = JsonConvert.SerializeObject(personList);

这是jsonString的结果

[{"Name":"Person1","Age":20,"Address":"addr1"},
{"Name":"Person2","Age":22,"Address":"addr2"},
{"Name":"Person1","Age":25,"Address":"addr3"}]

以下是我的预期结果，那么我该怎么做呢？

{
    Person1:{"Name":"Person1","Age":20,"Address":"addr1"},
    Person2:{"Name":"Person2","Age":22,"Address":"addr2"},
    Person3:{"Name":"Person3","Age":25,"Address":"addr3"}
}

Answer 1

当我没有错的时候，你必须使用Dictionary<string, Person>。这应该以这种方式序列化它，你想要它。

如果不需要冗余数据，可以选择将属性[JsonIgnore]添加到Name。

编辑：您可以使用自定义 JsonConverter：Newtonsoft.Json 将集合序列化（使用索引器）作为字典直接序列化到字典

Answer 2

public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
    public string Address { get; set; }
    // constructor
    public Person(string name, int age, string address){
        this.Name = name;
        this.Age = age;
        this.Address = address;
    }
 }

然后

 List<person>People = new List<person>();
 People.Add(new Person("name1", 1, "address1"));
 People.Add(new Person("name2", 2, "address2"));
 People.Add(new Person("name3", 3, "address3"));

string jsonString = JsonConvert.SerializeObject(People);

然后在客户端上，省略有关将其提供给客户端的部分

var people = JSON.parse(jsonString)