ReactJS切换按钮打开菜单

Question

i构建了React组件Toggle Menu，该组件由按钮触发。初始打开后，我看不到菜单打开/关闭。在如何开始解决此问题的情况下有点丢失...这是我用于参考如何使用ReactJS

构建滑动菜单的示例

export default class ToggleMenu extends React.Component {
  showRight = () => {
    this.right.show();
  }

  constructor(props) {
    super(props);
    this.showRight = this.showRight.bind(this);
  }
  render() {
    return (
      <div>
        <button onClick={this.showRight}>Show Right Menu!</button>
        <Menu ref={right => this.right = right} alignment="right">
        <MenuItem hash="first-page">First Page</MenuItem>
        <MenuItem hash="second-page">Second Page</MenuItem>
        <MenuItem hash="third-page">Third Page</MenuItem>
      </Menu>
      </div>
    );
  }
}

export default class Menu extends React.Component {
    state = {
      visible: false,
    };
    show() {
      this.setState({ visible: true });
    }
    hide() {
      this.setState({ visible: false });
    }
    render() {
      const { visible } = this.state;
      return (
        <div className="menu">
          {
            visible &&
              <div className={this.props.alignment}>{this.props.children}</div>
          }
        </div>
      );
    }
}

Answer 1

通过将状态移至主togglemenu，您可以使此组件保持菜单的可见性。

class ToggleMenu extends React.Component {
    constructor(props) {
        super(props);
        this.state = {
            visible: false  
        };
        this.toggleMenu = this.toggleMenu.bind(this);
    }
    toggleMenu() {
        this.setState({visible: !this.state.visible})
    }
    render() {
        return (
            <div>
                <button onClick={this.toggleMenu}>Show Right Menu!</button>
                {this.state.visible && <Menu alignment="right">
                <MenuItem hash="first-page">First Page</MenuItem>
                <MenuItem hash="second-page">Second Page</MenuItem>
                <MenuItem hash="third-page">Third Page</MenuItem>
                </Menu>}
            </div>
        );
    }
}

这使我可以将您的菜单更改为无状态组件：

const Menu = ({alignment, children}) => (
    <div className="menu">
        <div className={alignment}>{children}</div>
    </div>
);

我在这里创建了一个WebPackbin(现在使用动画(：https：//www.webpackbin.com/bins/bins/-klh1vm-n4rdckebkk67

对于过渡和动画，我建议您查看https://github.com/reaectjs/reaect-transition-group

Answer 2

export default class ToggleMenu extends React.Component {
  constructor(props) {
    super(props);
    this.state = { rightMenu: false }
    this.showRight = this.showRight.bind(this);
  }
  showRight = () => {
    this.setState({ rightMenu: !this.state.rightMenu })
  }
  render() {
    return (
      <div>
      <button onClick={this.showRight}>Show Right Menu!</button>
      <Menu className={ this.state.rightMenu ? "displayBlock" : "displayNone"} ref={right => this.right = right} alignment="right">
      <MenuItem hash="first-page">First Page</MenuItem>
      <MenuItem hash="second-page">Second Page</MenuItem>
      <MenuItem hash="third-page">Third Page</MenuItem>
      </Menu>
      </div>
    );
  }
}
//Style code
.displayBlock{ display: block }
.displayNone{ display: none} 

Answer 3

class App extends React.Component {
  state = {
    messageVisibility: true
  }  
  toggleMessage = () => {
    this.setState({
      messageVisibility: !this.state.messageVisibility
    })
  }
  render() {
    return(
      <div>           
        <button onClick={this.toggleMessage}>Toggle Message</button>
        {this.state.messageVisibility ? <p>Toggle Content</p> : null}        
      </div>
    )
  }
}

Answer 4

将EventListener添加到您的按钮。

//Add ID to the button
<button id = "toggle"></button>
//Outside the render method
   document.getElementById('toggle').addEventListener('click', function(e){
    If(e.target.style.display="none") {
        this.right.show()
    } Else {
        this.right.hide()
    }

}(