需要显示下一步:来自表用户名的所有fname和lname具有" admin"的位置,并在'abc'Company(name_company(中工作,并在子句中。
。create table company
(
CODE_COMPANY char(30),
NAME_COMPANY varchar2(30) not null,
MAIL_COMPANY varchar2(30) null,
constraint PK_CODE_COMPANY primary key (CODE_COMPANY),
);
create table USERNAME
(
NAME_USERNAME varchar2(30),
USER_LOCATION number,
fNAME varchar2 (30) not null,
lNAME varchar2 (30) not null,
PHONE_USER char(13) null,
USER_POSITION varchar2 (30),
check (USER_POSITION in('Admin', 'Superadmin', 'Technician', 'Student')),
constraint PK_NAME_USERNAME primary key (NAME_USERNAME),
constraint FK_USER_LOCATION foreign key (USER_LOCATION) references uLOCATION (LOCATION)
);
create table uLOCATION
(
LOCATION number,
CODE_COMPANY char(30),
NAME_LOCATION varchar2(30) not null,
FLOOR_LOCATION varchar2(10),
check (FLOOR_LOCATION in ('MAIN_FLOOR', '1ST FLOOR', '2ND FLOOR', '3RD FLOOR')),
constraint PK_LOCATION primary key (LOCATION),
constraint FK_CODE_COMPANY_L foreign key (CODE_COMPANY) references company (CODE_COMPANY),
);
如果我正确理解您的问题,则需要以下查询。不确定为什么您会使用IN代替标准=,但是我两者都将其包含在一个评论中。
select
user.fName,
user.lName
from
username as user
inner join ulocation as location
on location.location = user.user_location
inner join company as company
on company.code_company = location.code_company
where
user.user_position = 'Admin'
and name_company in ('A','B','C') -- not needed if only checking for one company
-- if only one company, change to: name_company = 'ABC'
我认为您正在寻找:
select u.*
from username u
where u.user_position = 'admin' and
u.ulocation in (select l.location
from ulocation l join
ucompany c
on l.code_company = c.code_company
where c.name_company = 'ABC'
);