使用 Golang 重组 Json

Question

我有以下JSON响应：

[
      {
        "talent_id": "b520ad50-5302-45ce-9121-5ff42d67b4fb",
        "platform": "facebook",
        "posts": [
          {
            "insights": [
              {
                "name": "post_impressions_organic_unique",
                "values": [
                  {
                    "value": 1828
                  }
                ]
              },
              {
                "name": "post_stories_by_action_type",
                "values": [
                  {
                    "like": 42
                  }
                ]
              }
            ],
            "type": "photo",
            "post_id": "24225267232_10154099759037233"
          },
          {
            "insights": [
              {
                "name": "post_impressions_organic_unique",
                "values": [
                  {
                    "value": 864
                  }
                ]
              },
              {
                "name": "post_stories_by_action_type",
                "values": [
                  {
                    "like": 19
                  }
                ]
              }
            ],
            "type": "photo",
            "post_id": "24225267232_10154099756677233"
          }
        ]
      }
    ]

我需要将其重组/展平为这样的东西：

{
    "talent_id": "b520ad50-5302-45ce-9121-5ff42d67b4fb",
    "platform": "facebook",
    "posts": [{
        "post_id": "24225267232_10154051404062233",
        "type": "photo",
        "organic_impressions_unique": 8288,
        "post_story_actions_by_type": {
            "shares": 234,
            "comments": 838,
            "likes": 8768
        }
    }, {
        "post_id": "24225267232_10154051404062233",
        "type": "photo",
        "organic_impressions_unique": 8288,
        "post_story_actions_by_type": {
            "shares": 234,
            "comments": 838,
            "likes": 8768
        }
    }]
}

我正在使用结构来映射 JSON 响应：

type JsonData struct {
    TalentID string `json:"talent_id"`
    Platform string `json:"platform"`
    Posts []struct {
        PostID string `json:"post_id"`
        Type string `json:"type"`
        Insights []struct {
            //Data []map[string]interface{}
            Name   string `json:"name"`
        } `json:"insights"`
    } `json:"posts"`
}

我的问题是帖子中的数据以及如何映射它，我正在使用地图来填充数据并封送它以生成 JSON 的新结构。

这是我的代码：

    messages := [] JsonData{}
    json.Unmarshal(body, &messages)
    m := make(map[string]interface{})
    m["talent_id"] = messages[0].TalentID
    m["platform"] = messages[0].Platform
    for _, p := range messages[0].Posts {
        for _, i := range p.Insights {
            // here is where I got lost and couldn't know how to fill the data inside the posts
        }
    }

    jsonString, err := json.Marshal(m)
    if err != nil {
        fmt.Println("error:", err)
    }
    fmt.Println(string(jsonString))

附言post_impressions_organic_unique和post_stories_by_action_type指标不是静态的，它们可以更改或在此处返回其他键

Answer 1

保持结构为：

type NameValue struct {
    Name string `json:"name"`
    Values []map[string]interface{} `json:"values"`
}
type JsonData struct {
    TalentID string `json:"talent_id"`
    Platform string `json:"platform"`
    Posts []struct {
        PostID string `json:"post_id"`
        Type string `json:"type"`
        Insights []NameValue `json:"insights"`
    } `json:"posts"`
}

创建另一个类似于下面的结构：

type JsonDataRes struct {
    TalentID string `json:"talent_id"`
    Platform string `json:"platform"`
    Posts []map[string]interface{} `json:"posts"`
}

在

JsonData结构中拥有数据后，循环访问见解对象，并手动为新的JsonDataRes对象以及帖子[]map[string]interface{}中的PostId和Type值分配值