如何最小化文件搜索运行时复杂性

Question

我编写了一个应用程序，该应用程序是一个允许执行各种命令的自定义控制台。其中一个命令允许根据其名称的一部分找到文件的完整路径。输入数据是一个字符串，其等于文件的部分全名。

我的问题是 - 如何尽可能最小化搜索代码运行时复杂性？

这是命令的代码：

using CustomConsole.Common;
using System;
using System.Collections.Generic;
using System.IO;
namespace Shell_Commander.Commands
{
    class FindFileCommand : ICommand
    {
        private string _findFileCommandName = "findfile";
        public string Name { get { return _findFileCommandName; } set { _findFileCommandName = value; } }
        public string Execute(string parameters)
        {
            var fileLocations = new Dictionary<string, bool>();
            try
            {
                var splittedParameters = parameters.Split(" ");
                var initialLocation = splittedParameters[0];
                var fileName = splittedParameters[1];
                foreach (var filePath in Directory.GetFiles(initialLocation, "*.*", SearchOption.A­llDirectories))
                {
                    fileLocations.Add(filePath, false);
                    if (Path.GetFileName(filePath) == fileName || Path.GetFileNameWithoutExtension(filePath) == fileName)
                    {
                        fileLocations[filePath] = true;
                    }
                }
            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.Message);
            }
            bool fileFound = false;
            string returnedOutput = "";
            foreach (var location in fileLocations.Keys)
            {
                if (fileLocations[location])
                {
                    returnedOutput += $"The file found in path: {location}n";
                    Console.Write(returnedOutput);
                    fileFound = true;
                }
            }
            if (!fileFound)
            {
                returnedOutput = "The file not found in this path";
                Console.WriteLine(returnedOutput);
                return returnedOutput;
            }
            return returnedOutput;
        }
    }
}

示例 - 对于输入参数" C： temp Test"，输出可以是：

The file found in path: c:temptest.json
The file found in path: c:temptest.json
The file found in path: c:temptest.xml
The file found in path: c:temptest.json
The file found in path: c:temptest.xml
The file found in path: c:temptesttest.json

Answer 1

您可以简单地像这样

var fileLocations  =  Directory.GetFiles(initialLocation, $"{filePath}.*", SearchOption.A­llDirectories);
 foreach (var location in fileLocations)
 {
       returnedOutput += $"The file found in path: {location}n";
       Console.Write(returnedOutput);
 }

其余代码也可以简化。