class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource,UISearchBarDelegate,UISearchDisplayDelegate{
@IBOutlet weak var recipeTable: UITableView!
@IBOutlet weak var searchbarValue: UISearchBar!
// search functionality
var filteredAnswers: [JSON]?
func searchBarSearchButtonClicked(_ searchBar: UISearchBar){
self.filteredAnswers?.removeAll()
if (searchBar.text?.isEmpty)! {
self.filteredAnswers = self.recipes } else {
if self.recipes.count > 0 {
for i in 0...self.recipes.count - 1 {
let answer = self.recipes[i] as [Dictionary<String, AnyObject>]
if answer.title.range(of: searchBar.text!, options: .caseInsensitive) != nil {
self.filteredAnswers.append(answer)
}
}
}
}
recipeTable.reloadData();
recipeTable.reloadInputViews();
searchBar.resignFirstResponder()
}
//end search parameters
// tableview functionionalitys
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}
// tableview functionalities
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as! RecipeTableViewCell
cell.recipeLabel.text = recipes[indexPath.row].title
//cell.textLabel?.text = recipe.title
//cell.imageView?.image = recipe.imageUrl
return cell
}
// structs for json
struct Root : Decodable {
let count : Int
let recipes : [Recipe]
}
struct Recipe : Decodable { // It's highly recommended to declare Recipe in singular form
let recipeId : String
let imageUrl, sourceUrl, f2fUrl : URL
let title : String
let publisher : String
let socialRank : Double
let page : Int?
let ingredients : [String]?
}
//recipes is array of Recipes
var recipes = [Recipe]() // array of recipes
//unfiltered recipes to put into search
var filteredRecipes = [Recipe]()
fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9"
//.data(using: .utf8)!
//let somedata = Data(jsonURL.utf8)
guard let url = URL(string: jsonURL) else{return}
URLSession.shared.dataTask(with: url) {(data, response , err) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}
//print(String(data: data, encoding: .utf8))
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
let result = try decoder.decode(Root.self, from: data)
self.recipes = result.recipes
//print(result.recipes)
self.recipeTable.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}
override func viewDidLoad() {
super.viewDidLoad()
//search functionalities
self.searchbarValue.delegate = self
//call json object
getRecipes()
}
}
我正在尝试实现一个搜索栏，它从JSON对象中获取成分，并在我的表视图中显示包含这些成分的食谱。我希望有一些最佳实践和帮助。我尝试了几种不同的策略，但似乎都不起作用。
这是我尝试实现的最后一个，但我在搜索功能中遇到了错误。
searchBarSearchButtonClicked中的self.recipes.count无法赋值类型为'[ViewController.Precipe]'到类型为'JSON]？但我在-中也遇到了断言失败
[UISearchResultsTableView_dequeueReusableCellWithIdentifier:forIndexPath:usingPresentationValues:]
我希望得到帮助，但也要改进并找到最好的方法。谢谢
首先，过滤配方的逻辑无法工作，而且效率非常低。你似乎是从一个完全无关的来源复制粘贴了代码。
基本上，数据源数组的类型和筛选数组的类型必须相同，因此必须使用filteredRecipes而不是filteredAnswers。
使用filter和contains过滤具有匹配成分的配方
func searchBarSearchButtonClicked(_ searchBar: UISearchBar){
filteredRecipes.removeAll()
if let searchText = searchBar.text, !searchText.isEmpty {
self.filteredRecipes = self.recipes.filter { recipe in
guard let ingredients = recipe.ingredients else { return false }
return ingredients.contains { $0.range(of: searchText, options: .caseInsensitive) != nil }
}
} else {
self.filteredRecipes = self.recipes
}
recipeTable.reloadData();
recipeTable.reloadInputViews();
searchBar.resignFirstResponder()
}
实际上，这个代码应该在委托方法中执行
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String)
而不是searchBarSearchButtonClicked
非常重要的是，您必须添加一个布尔属性来指示isSearching，并且在所有相关的数据源和委托方法中，如果isSearching为true，则必须添加一条条件来显示filteredRecipes的数据。