l=[1,4,5,6,3,2,4,0]
我希望出来
成为newlist=[14,56,32,40]
我试过了
for i in l[::2]:
newlist.append(i)
怎么办
您可以在列表推导式中使用zip()
函数:
>>> lst = [1,4,5,6,3,2,4,0]
>>> [i*10+j for i,j in zip(lst[0::2],lst[1::2])]
[14, 56, 32, 40]
作为用奇数项覆盖列表的更通用的方法,您可以使用itertools.izip_longest
(在python 3.X itertools.zip_longest
中):通过将 0 作为fillvalue
参数传递:
>>> lst=[1,4,5,6,3,2,4]
>>>
>>> from itertools import izip_longest
>>> [i*10+j for i,j in izip_longest(lst[0::2],lst[1::2], fillvalue=0)]
[14, 56, 32, 40]
另一种解决方案,只是为了好玩
lst = [1,4,5,6,3,2,4,0]
it = iter(lst)
for i in it:
num = int(str(i) + str(next(it)))
print num
lst = [1,4,5,6,3,2,4,0,1]
length = len(lst)
newList = [i*10+j for i,j in zip(lst[::2],lst[1::2])]
if length % 2 == 1:
newList.append(lst[-1]*10)
print newList
输出:
[14, 56, 32, 40, 10]