我对python(以及一般的编程)很陌生。下面粘贴的代码用于编辑现有 csv。但是我收到一个错误。错误是
Traceback (most recent call last):
File "C:UsersSamsung PcDesktophungrypy1hungry_data.py", line 34, in <module>
writer.writeheader()
File "C:UsersSamsung PcAppDataLocalProgramsPythonPython36-32libcsv.py", line 144, in writeheader
self.writerow(header)
File "C:UsersSamsung PcAppDataLocalProgramsPythonPython36-32libcsv.py", line 155, in writerow
return self.writer.writerow(self._dict_to_list(rowdict))
File "C:UsersSamsung PcAppDataLocalProgramsPythonPython36-32libtempfile.py", line 483, in func_wrapper
return func(*args, **kwargs)
TypeError: a bytes-like object is required, not 'str'
[Finished in 0.5s]
我试图寻找答案,它似乎是从二进制到字符串的类型不匹配。我尝试以"r"而不是"rb"打开文件,但是是相同的错误。请帮忙。代码如下。
import csv
import shutil
from tempfile import NamedTemporaryFile
def get_length(file_path):
with open("data.csv", "r") as csvfile:
reader = csv.reader(csvfile)
reader_list = list(reader)
print(reader_list)
return len(reader_list)
def append_data(file_path, name, email):
fieldnames = ['id', 'name', 'email'
next_id = get_length(file_path)
with open(file_path, "a", newline = '') as csvfile:
writer = csv.DictWriter(csvfile, fieldnames=fieldnames)
writer.writeheader()
writer.writerow({
"id": next_id,
"name": name,
"email": email,
})
append_data("data.csv", "Niraj", "test@test.com")
filename = "data.csv"
temp_file = NamedTemporaryFile(delete = False)
with open(filename, "r") as csvfile, temp_file:
reader = csv.DictReader(csvfile)
fieldnames = ['id','name','email','amount','sent']
writer = csv.DictWriter(temp_file, fieldnames = fieldnames)
writer.writeheader()
for row in reader:
writer.writerow({
"id" : row["id"],
"name" : row["name"],
"email": row["email"],
"amount": "1234.34",
"sent": "",
})
#shutil.move(temp_file.name. filename)
不应同时读取和写入同一文件:
with open(filename, "r") as csvfile, temp_file:
即使您为此文件指定了两个名称,它们也指向磁盘中的同一文件,请将其更改为:
with open(filename, "r") as csvfile, open('temp_file.csv', 'w') as temp_file:
你在做什么:
temp_file = NamedTemporaryFile(delete = False)
with open(filename, "r") as csvfile, temp_file:
, temp_file
部分严格来说什么都不做。您必须打开文件进行写入...
之后,您将使用 temp_file
作为输出文件句柄,但它实际上是一个字符串,因此您会收到消息。
您要执行此操作:
with open(filename, "r") as csvfile, open(temp_file,"w",newline='') as outfile:
然后使用 outfile
,而不是temp_file
:
writer = csv.DictWriter(outfile, fieldnames = fieldnames)
旁白:不要使用 writer.writeheader()
:无论如何,标题是写的,你会得到两次。