扫雷程序java x和y在2d数组上切换

Question

我正在为《扫雷》创建一个代码，并试图实现一个GUI。但问题是，当我运行代码并玩游戏时，我在棋盘上点击的位置显示的是答案板上该位置的y,x坐标，而不是x, y坐标。我一直在试图解决这个问题，但我看不出来。我想这可能是我创建董事会的方式，但我尝试了我能想到的所有方法。

class Board{
public MsGUI gui;
private static char[][] userBoard;
private static char[][] solutionBoard;
private static int boundSize = 5;
public Board(){
 userBoard = new char[][]   {{'-','-','-','-','-'},
                              {'-','-','-','-','-'},
                              {'-','-','-','-','-'},
                              {'-','-','-','-','-'},
                              {'-','-','-','-','-'}};  
 solutionBoard = new char[][] {{'0','2','B','2','0'},
                {'0','3','B','3','0'},
                {'1','3','B','3','1'},
                {'B','1','3','B','2'},
                {'1','1','2','B','2'}};
 return;
    }    
private static void printBoard(char[][] board){      
     for (int x = 0; x < boundSize; x++){
        for(int y = 0; y < boundSize; y++){
            System.out.print(" " + Character.toString(board[x][y]));
        }
        System.out.println("");
    }        
    System.out.println("");
}
public void flagCell(int xCoordinate, int yCoordinate){
    userBoard[xCoordinate][yCoordinate] = 'F';

}
public boolean isFlagged(int xCoordinate,int yCoordinate){
if(userBoard[xCoordinate][yCoordinate] == 'F'){
return true;
}
else{
return false;
}
}
public int getHeight() {
return userBoard.length;
}
public int getWidth(){
return userBoard[0].length;
}
public char getValue(int xCoordinate, int yCoordinate) {
return userBoard[xCoordinate][yCoordinate];
}
private static boolean checkIfAlreadyMarked(int xCoordinate, int yCoordinate)
{
    boolean marked = false;
    if (Character.toString(userBoard[xCoordinate][yCoordinate]).equals("-") == false)
    {
        marked = true;
    }
    return marked;
}

public void revealCell(int xCoordinate, int yCoordinate){
    int count = 0;
for(int i = 0;i < userBoard.length;i++){
    for(int J = 0;J < userBoard[i].length;J++){
        if(userBoard[i][J] != '-'){
        count = count + 1;
    }
}
if(count == 19){
gui.win("you won");
return;
}
}
    if(solutionBoard[xCoordinate][yCoordinate] == 'B'){
        userBoard[xCoordinate][yCoordinate] = solutionBoard[xCoordinate][yCoordinate];
        gui.lose("You lost. Better luck next time!");
        return;
    }   
    if(solutionBoard[xCoordinate][yCoordinate] != '0'){
        userBoard[xCoordinate][yCoordinate] = solutionBoard[xCoordinate][yCoordinate];
    }else{
        userBoard[xCoordinate][yCoordinate] = solutionBoard[xCoordinate][yCoordinate];
        for(int i = 1; i > -2; i--){
            if(xCoordinate-i >= solutionBoard.length || xCoordinate-i < 0)
                continue;
            for(int z = 1; z > -2; z--){
                if(yCoordinate-z >= solutionBoard[xCoordinate].length || yCoordinate-z < 0)
                    continue;

                else if(userBoard[xCoordinate-i][yCoordinate-z] == 'F' || userBoard[xCoordinate-i][yCoordinate-z] != '-')
                    continue;
                else{
                    revealCell(xCoordinate-i, yCoordinate-z);
                }
            }
        }   
    }


}

  public void unflagCell(int xCoordinate, int yCoordinate){
userBoard[xCoordinate][yCoordinate]='-';
}
public static void main(String[] args){
Board b = new Board();
b.gui = new MsGUI(b);
b.gui.setVisible(true);

}
}

Answer 1

您初始化solutionBoard的方式不是您期望的那样。如果你得到solutionBoard[0]，你没有访问第一列(这将与我认为是你的理解一致)，但第一行(二维数组的第一项):{'0'，'2'，'B'，'2'，'0'}

所以，如果你想让x作为行索引，y作为列索引，并且仍然保持这个"可读"初始化，你必须在访问数组时交换索引。但这只会帮助您解决一个问题-开始时人类可读的数组赋值，但我认为您将来会后悔这个决定。

编辑:您可以根据需要初始化数组，并且仍然使用如下的可读格式:

String readableBoard =
            "0 2 B 2 0;" +
            "0 3 B 3 0;" +
            "1 3 B 3 1;" +
            "B 1 B B 2;" +
            "1 1 2 B 2";
char[][] board = initBoard(readableBoard);
....
private char[][] initBoard(String readableBoard){
    char[][] board = new char[5][5];
    String[] rows = readableBoard.split(";");
    String[] fields = null;
    for (int y = 0; y<rows.length;y++){
        fields = rows[y].split(" ");
        for (int x = 0; x<fields.length; x++){
            board[x][y]=fields[x].charAt(0);
        }
    }
    return board;
}

现在当你调用

board[2][0]

你会得到'B'

Answer 2

如果您查看嵌套的for循环，您将打印出列，而不是我认为需要的行。试着切换for循环，先遍历y，再遍历x。

   for (int y = 0; y < boundSize; y++){
    for(int x = 0; x < boundSize; x++){
        System.out.print(" " + Character.toString(board[x][y]));
    }
    System.out.println("");
}        
System.out.println("");