我试图创建一个视图,可以滑动以解散,但它可以撤消。项目有一个背景和前景内的FrameView
。我在ItemTouchHelper.Callback
中重写onChildDraw
,像这样:
@Override
public void onChildDraw(Canvas c, RecyclerView recyclerView, RecyclerView.ViewHolder viewHolder,
float dX, float dY, int actionState, boolean isCurrentlyActive) {
if (actionState == ItemTouchHelper.ACTION_STATE_SWIPE) {
if (viewHolder instanceof ItemViewHolder) {
ItemViewHolder holder = (ItemViewHolder) viewHolder;
holder.foreground.setTranslationX(dX);
}
} else {
super.onChildDraw(c, recyclerView, viewHolder, dX, dY, actionState, isCurrentlyActive);
}
}
一切正常,直到我尝试撤销基于用户操作的滑动动作,像这样:
foreground.animate()
.translationX(0)
.setDuration(150);
确实把实际视图带回到它的位置,但是如果用户试图再次滑动那个项目,背景再次显示,并且由于某种原因onChildDraw被调用,dX参数大于屏幕的宽度。点击该项目将显示背景视图一秒钟,然后前景通常可以取消。我该如何解决这个问题?
解决方法是使用ItemTouchHelper.Callback
的getDefaultUIUtil()
函数。工作代码如下:
@Override
public void onChildDraw(Canvas c, RecyclerView recyclerView, RecyclerView.ViewHolder viewHolder,
float dX, float dY, int actionState, boolean isCurrentlyActive) {
if (actionState == ItemTouchHelper.ACTION_STATE_SWIPE) {
if (viewHolder instanceof TrackerListAdapter.ItemViewHolder) {
TrackerListAdapter.ItemViewHolder holder =
(TrackerListAdapter.ItemViewHolder) viewHolder;
getDefaultUIUtil().onDraw(c, recyclerView, holder.foreground, dX, dY, actionState, isCurrentlyActive);
}
} else {
super.onChildDraw(c, recyclerView, viewHolder, dX, dY, actionState, isCurrentlyActive);
}
}