Python minidom:列出每个父标记的子节点属性

Question

我有，

<parent id="1">
    <child id="white"></child>
    <child id="red"></child>
</parent>
<parent id="2">
    <child id="green"></child>
    <child id="gray"></child>
</parent>

我需要这个输出，

1 
 white
 red
2
 green
 gray

，我就是这么做的

parent = xmldoc.getElementsByTagName('parent')
for item in parent:
    child = xmldoc.getElementsByTagName('child')
    child_id = child.getAttribute('id')
    for child_id in child:
        print child_id

当然，我错了，但不知道如何循环这些父ID并单独收集每个列表。我很感激你的帮助！

Answer 1

试试这个

import xml.dom.minidom as minidom
a = '<parent id="1"><child id="white"></child><child id="red"></child></parent>'
dom = minidom.parseString(a)
for parent in dom.childNodes:
    print parent.getAttribute('id')
    for child in parent.childNodes:
        print '  %s' % child.getAttribute('id')

Answer 2

因为您正在猜测代码和语法：

import xml.dom.minidom
s =  """<?xml version="1.0"?>
<container>
<parent id="1">
    <child id="white"></child>
    <child id="red"></child>
</parent>
<parent id="2">
    <child id="green"></child>
    <child id="gray"></child>
</parent>
</container>
"""

xmldoc = xml.dom.minidom.parseString(s)
parent = xmldoc.getElementsByTagName('parent')
for item in parent:
    print item.getAttribute('id')
    for child in item.getElementsByTagName('child'):
        print child.getAttribute('id')