如果我有一个重载的赋值运算符,需要深度复制一个类,我该怎么做?类Person包含一个Name类
Person& Person::operator=(Person& per){
if (this==&per){return *this;}
// my attempt at making a deep-copy but it crashes
this->name = *new Name(per.name);
}
在名称类中复制构造函数和赋值运算符
Name::Name(Name& name){
if(name.firstName){
firstName = new char [strlen(name.firstName)+1];
strcpy(firstName,name.firstName);
}
Name& Name::operator=(Name& newName){
if(this==&newName){return *this;}
if(newName.firstName){
firstName = new char [strlen(newName.firstName)+1];
strcpy(firstName,newName.firstName);
return *this;
}
我将利用现有的复制构造函数、析构函数和添加的swap()
函数:
Name& Name::operator= (Name other) {
this->swap(other);
return *this;
}
我正在执行的所有复制作业看起来都像这个实现。缺少的swap()
函数对编写来说也是微不足道的:
void Name::swap(Name& other) {
std::swap(this->firstName, other.firstName);
}
对于CCD_ 3也是如此。