创建包含数组的JObject时出错

Question

我正在尝试重新创建这个json:

{
    "auth": {
        "identity": {
            "methods": [
                "password"
            ],
            "password": {
                "user": {
                    "id": "90551bd1bcf6474dba09c96617a33638",
                    "password": "hoeIX1.i-.M]wiu9"
                }
            }
        },
        "scope": {
            "project": {
                "id": "2440e4fa1725452cb2e14506cb5d63ec"
            }
        }
    }
}

现在我正在做这个：

JObject auth = new JObject(
    new JProperty("auth", new JObject(
        new JProperty("identity", new JObject(
            new JProperty("method",JArray.Parse("["password"]")),
            new JProperty("password", new JObject(
                new JProperty("user", new JObject(
                    new JProperty("id", JValue.CreateString(identityWithProject.Username)),
                    new JProperty("password", JValue.CreateString(identityWithProject.ProjectName))))))),
        new JProperty("scope", new JObject(
            new JProperty("project", new JObject(
                new JProperty("id", JValue.CreateString(identityWithProject.ProjectName))))))))));

我得到这个错误：

"无法将Newtonsoft.Json.Linq.JProperty添加到Newtonsoft.Json.Linq.JArray。"

不工作的线路是：

new JProperty("method",JArray.Parse("["password"]"))

如果我删除了JArray部分，它工作得很好，我如何修复它，使它与数组部分一起工作？我发现的大多数例子都是JObjects数组，但事实并非如此。谢谢

Answer 1

看起来有一个放错地方的)，这很有效：

var auth = new JObject(
    new JProperty("auth", new JObject(
        new JProperty("identity", new JObject(
            new JProperty("methods", JArray.Parse("["password"]")),
            new JProperty("password", new JObject(
                new JProperty("user", new JObject(
                    new JProperty("id", JValue.CreateString(identityWithProject.Username)),
                    new JProperty("password", JValue.CreateString(identityWithProject.ProjectName)))))))), // 8 x ')'
        new JProperty("scope", new JObject(
            new JProperty("project", new JObject(
                new JProperty("id", JValue.CreateString(identityWithProject.ProjectName))))))))); // 9 x ')'

我刚从最后一行移了一个)到最后一行的第三行。

此外，如果属性"method"要处理您的样本，则应将其命名为"methods"。此外，在创建JProperties时确实没有理由使用JValue.CreateString，正如@Steven Brickner所指出的，您可以将JArray.Parse("["password"]")简化为new JArray("password")。

它可能更详细，但为了可读性，这里它是完全缩进的：

var auth = 
    new JObject(
        new JProperty("auth", 
            new JObject(
                new JProperty("identity", 
                    new JObject(
                        new JProperty("methods", new JArray("password")),
                        new JProperty("password", 
                            new JObject(
                                new JProperty("user", 
                                    new JObject(
                                        new JProperty("id", identityWithProject.Username),
                                        new JProperty("password", identityWithProject.ProjectName)
                                    )
                                )
                            )
                        )
                    )
                ),
                new JProperty("scope", 
                    new JObject(
                        new JProperty("project", 
                            new JObject(
                                new JProperty("id", identityWithProject.ProjectName)
                            )
                        )
                    )
                )
            )
        )
    );